"""
Given a list of integers, made up of (hopefully) a small number of long runs
of consecutive integers, compute a representation of the form
((start1, end1), (start2, end2) ...). Then answer the question "was x present in the original list?" in time O(log(# runs)). """
import bisect from typing import List, Tuple
def intranges_from_list(list_: List[int]) -> Tuple[int, ...]: """Represent a list of integers as a sequence of ranges:
((start_0, end_0), (start_1, end_1), ...), such that the original
integers are exactly those x such that start_i <= x < end_i for some i.
Ranges are encoded as single integers (start << 32 | end), notas tuples. """
sorted_list = sorted(list_)
ranges = []
last_write = -1 for i in range(len(sorted_list)): if i + 1 < len(sorted_list): if sorted_list[i] == sorted_list[i + 1] - 1: continue
current_range = sorted_list[last_write + 1 : i + 1]
ranges.append(_encode_range(current_range[0], current_range[-1] + 1))
last_write = i
def intranges_contain(int_: int, ranges: Tuple[int, ...]) -> bool: """Determine if `int_` falls into one of the ranges in `ranges`."""
tuple_ = _encode_range(int_, 0)
pos = bisect.bisect_left(ranges, tuple_) # we could be immediately ahead of a tuple (start, end) # with start < int_ <= end if pos > 0:
left, right = _decode_range(ranges[pos - 1]) if left <= int_ < right: returnTrue # or we could be immediately behind a tuple (int_, end) if pos < len(ranges):
left, _ = _decode_range(ranges[pos]) if left == int_: returnTrue returnFalse
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