**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 EMBEDDED COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR019.PCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED C BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE REFERENTIAL INTEGRITY CONSTRAINT FOR * SQL. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.7 <referential constraint definition> * <referential constraint definition>::= * FOREIGN KEY (<referencing columns>) * <references specification> * <references specification>::= * REFERENCES <referenced table and columns> * <referencing columns>::= * <reference column list> * <refereced table and columns>::= * <table name>((<reference column list> * <reference column list>::= * <column name>({,<column name>}...) * ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx EXECSQLSELECT
USER INTO :uidx FROM SUN.ECCO END-EXEC if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Embedded COBOL, cdr019.pco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME ******************** BEGIN TEST0365 *******************
* insert row into FOREIGN KEY TABLE EMP, check * referential integrity. TABLE EMP is also a PRIMARY * KEY TABLE to EXPERIENCE TABLE
DISPLAY" TEST0365 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (41,'Tom','China Architecture'," DISPLAY" 20,'Architecture',040553);" DISPLAY" " DISPLAY" INSERT INTO DEPT VALUES" DISPLAY" (20,'Architecture','Richard');" DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (41,'Tom','China Architecture'," DISPLAY" 20,'Architecture',040553);" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1 FROM EMP" DISPLAY" WHERE ENO = 41;" DISPLAY" " COMPUTE count1 = -1 EXECSQLINSERTINTO EMP VALUES
(41,'Tom','China Architecture',
20,'Architecture',040553) END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLINSERTINTO DEPT VALUES
(20,'Architecture','Richard') END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLINSERTINTO EMP VALUES
(41,'Tom','China Architecture',
20,'Architecture',040553) END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQLSELECTCOUNT(*) INTO :count1 FROM EMP
WHERE ENO = 41 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQL ROLLBACK WORK END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is less than 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 1" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND count1 = 1 AND code2 = 0) then EXECSQLINSERTINTO TESTREPORT
VALUES('0365','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0365','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD **************** END TEST 0365 **********
******************** BEGIN TEST0366 *******************
* insert row into PRIMARY KEY TABLE EMP, check * referential integrity. TABLE EMP is also a FOREIGN * KEY TABLE to TABLE DEPT
DISPLAY" TEST0366 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" DELETE FROM EXPERIENCE" DISPLAY" WHERE EXP_NAME = 'Tom' AND BTH_DATE = 040523;" DISPLAY" " DISPLAY" DELETE FROM EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1 FROM EMP" DISPLAY" WHERE ENO = 21;" COMPUTE count1 = -1 EXECSQLDELETEFROM EMP
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLDELETEFROM EXPERIENCE
WHERE EXP_NAME = 'Tom'AND BTH_DATE = 040523 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLDELETEFROM EMP
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQLSELECTCOUNT(*) INTO :count1 FROM EMP
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQL ROLLBACK WORK END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 NOT = 0 AND count1 = 0 AND code2 = 0) then EXECSQLINSERTINTO TESTREPORT
VALUES('0366','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0366','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD **************** END TEST 0366 **********
******************** BEGIN TEST0367 *******************
* Update middle table, check the effect of this table * as both PRIMARY TABLE (to upper level) and FOREIGN * TABLE (to lower level).
DISPLAY" TEST0367 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET ENAME = 'Thomas'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET DNAME = 'Agriculture'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET DNAME = 'Education'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM EMP" DISPLAY" WHERE DNO = 12 AND DNAME = 'Education'" DISPLAY" AND ENO = 21 AND ENAME = 'Tom';" DISPLAY" " COMPUTE count1 = -1 EXECSQL UPDATE EMP SET ENAME = 'Thomas'
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQL UPDATE EMP SET DNAME = 'Agriculture'
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQL UPDATE EMP SET DNAME = 'Education'
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM EMP
WHERE DNO = 12 AND DNAME = 'Education' AND ENO = 21 AND ENAME = 'Tom'END-EXEC MOVE SQLCODE TO SQL-COD EXECSQL ROLLBACK WORK END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is not equal to 0." DISPLAY" count1 is 1" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND code2 < 0 AND count1 = 1) then EXECSQLINSERTINTO TESTREPORT
VALUES('0367','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0367','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD ************************ END TEST0367 ************************
******************** BEGIN TEST0368 ******************* *The employee Tom in EMP, his name is changed into *Thomas, this will affect the integrity. DISPLAY" TEST0368 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET ENAME = 'Thomas'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (30,'Thomas','Languages & Operating
- " System'," DISPLAY" 12,'Computer',040523);" DISPLAY" " DISPLAY" UPDATE EXPERIENCE" DISPLAY" SET EXP_NAME = 'Thomas'" DISPLAY" WHERE EXP_NAME = 'Tom' AND BTH_DATE=040523;" DISPLAY" " DISPLAY" DELETE EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM EMP" DISPLAY" WHERE DNO = 12 AND ENO = 21 " DISPLAY" AND ENAME = 'Tom';" DISPLAY" " COMPUTE count1 = -1 EXECSQL UPDATE EMP SET ENAME = 'Thomas'
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 EXECSQLINSERTINTO EMP VALUES
(30,'Thomas','Languages & Operating System',
12,'Computer',040523) END-EXEC MOVE SQLCODE TO SQL-COD EXECSQL UPDATE EXPERIENCE SET EXP_NAME = 'Thomas'
WHERE EXP_NAME = 'Tom'AND BTH_DATE = 040523 END-EXEC MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 EXECSQLDELETEFROM EMP
WHERE ENO = 21 END-EXEC MOVE SQLCODE TO SQL-COD EXECSQLSELECTCOUNT(*) INTO :count1 FROM EMP
WHERE DNO = 12 AND ENO = 21 AND ENAME = 'Tom'END-EXEC MOVE SQLCODE TO SQL-COD EXECSQL ROLLBACK WORK END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND code2 = 0 AND count1 = 0) then EXECSQLINSERTINTO TESTREPORT
VALUES('0368','pass','PCO') END-EXEC MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else EXECSQLINSERTINTO TESTREPORT
VALUES('0368','fail','PCO') END-EXEC ADD 1 TO errcnt MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.pco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " EXECSQL COMMIT WORK END-EXEC MOVE SQLCODE TO SQL-COD ************************ END TEST0368 ************************
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
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