/* * __do_div64: perform a division with 64-bit dividend and 32-bit divisor. * * Note: Calling convention is totally non standard for optimal code. * This is meant to be used by do_div() from include/asm/div64.h only. * * Input parameters: * xh-xl = dividend (clobbered) * r4 = divisor (preserved) * * Output values: * yh-yl = result * xh = remainder * * Clobbered regs: xl, ip
*/
ENTRY(__do_div64)
UNWIND(.fnstart)
@ Test for easy paths first.
subs ip, r4, #1
bls 9f @ divisor is 0 or 1
tst ip, r4
beq 8f @ divisor is power of 2
@ See if we need to handle upper 32-bit result.
cmp xh, r4
mov yh, #0
blo 3f
@ Align divisor with upper part of dividend.
@ The aligned divisor is stored in yl preserving the original.
@ The bit position is stored in ip.
@ The division loop for needed upper bit positions.
@ Break out early if dividend reaches 0.
2: cmp xh, yl
orrcs yh, yh, ip
subscs xh, xh, yl
movsne ip, ip, lsr #1
mov yl, yl, lsr #1
bne 2b
@ See if we need to handle lower 32-bit result.
3: cmp xh, #0
mov yl, #0
cmpeq xl, r4
movlo xh, xl
retlo lr
@ The division loop for lower bit positions.
@ Here we shift remainer bits leftwards rather than moving the
@ divisor for comparisons, considering the carry-out bit as well.
mov ip, #0x80000000
4: movs xl, xl, lsl #1
adcs xh, xh, xh
beq 6f
cmpcc xh, r4
5: orrcs yl, yl, ip
subcs xh, xh, r4
movs ip, ip, lsr #1
bne 4b
ret lr
@ The top part of remainder became zero. If carry is set
@ (the 33th bit) this is a false positive so resume the loop.
@ Otherwise, if lower part is also null then we are done.
6: bcs 5b
cmp xl, #0
reteq lr
@ We still have remainer bits in the low part. Bring them up.
#if __LINUX_ARM_ARCH__ >= 5
clz xh, xl @ we know xh is zero here so...
add xh, xh, #1
mov xl, xl, lsl xh
mov ip, ip, lsr xh
#else
7: movs xl, xl, lsl #1
mov ip, ip, lsr #1
bcc 7b
#endif
@ Current remainder is now 1. It is worthless to compare with
@ divisor at this point since divisor can not be smaller than 3 here.
@ If possible, branch for another shift in the division loop.
@ If no bit position left then we are done.
movs ip, ip, lsr #1
mov xh, #1
bne 4b
ret lr
8: @ Division by a power of 2: determine what that divisor order is
@ then simply shift values around
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