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IDENTIFICATION DIVISION.
PROGRAM-ID. CDR004.
ENVIRONMENT DIVISION.
CONFIGURATION SECTION.
SOURCE-COMPUTER. xyz.
OBJECT-COMPUTER. xyz.
DATA DIVISION.
WORKING-STORAGE SECTION.
* EMBEDDED COBOL (file "CDR004.PCO")
****************************************************************
*
* COMMENT SECTION
*
* DATE 1989/04/07 EMBEDDED COBOL LANGUAGE
* NIST SQL VALIDATION TEST SUITE V6.0
* DISCLAIMER:
* This program was written by employees of NIST to test SQL
* implementations for conformance to the SQL standards.
* NIST assumes no responsibility for any party's use of
* this program.
*
* CDR004.PCO
* WRITTEN BY: SUN DAJUN
* TRANSLATED AUTOMATICALLY FROM EMBEDDED C BY CHRIS SCHANZLE
*
* THIS ROUTINE TESTS THE <CHECK> CONSTRAINT.
*
* REFERENCES
* AMERICAN NATIONAL STANDARD database language - SQL
* with Integrity Enhancement
*
* SECTION 6.8
* <check constraint definition>::=
* CHECK (<search condition>)
****************************************************************
EXEC SQL BEGIN DECLARE SECTION END-EXEC
01 count1 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
01 count2 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
01 uid PIC X(18).
01 uidx PIC X(18).
EXEC SQL END DECLARE SECTION END-EXEC
01 SQLCODE PIC S9(9) COMP.
01 errcnt PIC S9(4) DISPLAY SIGN LEADING SEPARATE.
01 code1 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
01 code2 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
01 SQL-COD PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
* date_time declaration *
01 TO-DAY PIC 9(6).
01 THE-TIME PIC 9(8).
PROCEDURE DIVISION.
P0.
MOVE "SUN" TO uid
CALL "AUTHID" USING uid
MOVE "not logged in, not" TO uidx
EXEC SQL SELECT
USER INTO :uidx FROM SUN.ECCO END-EXEC
if (uid NOT = uidx) then
DISPLAY "ERROR: User " uid " expected."
DISPLAY "User " uidx " connected."
DISPLAY " "
STOP RUN
END-IF
MOVE 0 TO errcnt
DISPLAY
"SQL Test Suite, V6.0, Embedded COBOL, cdr004.pco"
DISPLAY " "
DISPLAY
"59-byte ID"
DISPLAY "TEd Version #"
DISPLAY " "
* date_time print *
ACCEPT TO-DAY FROM DATE
ACCEPT THE-TIME FROM TIME
DISPLAY "Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME
******************** BEGIN TEST0309 ******************
*This procedure tests CHECK specification on two
*columns with AND.
* CHECK condition
* GRADE NOT IN (5,22) AND EMPNAME LIKE 'T%'
DISPLAY " TEST0309 "
DISPLAY " CHECK CONSTRAINTS "
DISPLAY " SQL with Integrity Enhancement section 6.8"
DISPLAY " - - - - - - - - - - - - - - - - - - - - - - - - "
DISPLAY " "
DISPLAY " INSERT INTO STAFF11"
DISPLAY " VALUES('E1','Thomas',0,'Deale');"
DISPLAY "code1 = SQLCODE;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF11"
DISPLAY " VALUES('E2','Dom',22,'Newyork');"
DISPLAY "code2 = SQLCODE;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF11"
DISPLAY " VALUES('E3','Susan',11,'Hawaii');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO :count1"
DISPLAY " FROM STAFF11;"
EXEC SQL DELETE FROM STAFF11 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF11
VALUES('E1','Thomas',0,'Deale') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code1
EXEC SQL INSERT INTO STAFF11
VALUES('E2','Tom',22,'Newyork') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code2
EXEC SQL INSERT INTO STAFF11
VALUES('E3','Susan',11,'Hawaii') END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL SELECT COUNT(*) INTO :count1
FROM STAFF11 END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " The correct answer is:"
DISPLAY " code1 < 0,code2 < 0,count1 = 1."
DISPLAY " Your answer is:"
DISPLAY " code1 = ", code1 ",code2 = ", code2
DISPLAY ",count1= ", count1
if (code1 NOT = 0 AND count1 = 1 ) then
EXEC SQL INSERT INTO TESTREPORT
VALUES('0309','pass','PCO') END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " *** pass *** "
else
EXEC SQL INSERT INTO TESTREPORT
VALUES('0309','fail','PCO') END-EXEC
ADD 1 TO errcnt
MOVE SQLCODE TO SQL-COD
DISPLAY " cdr004.pco *** fail *** "
END-IF
DISPLAY "================================================"
DISPLAY " "
EXEC SQL COMMIT WORK END-EXEC
MOVE SQLCODE TO SQL-COD
****************** END TEST0309 *****************************
******************** BEGIN TEST0310 ******************
*This procedure tests if x NOT IN and NOT x IN of the
*CHECK specification has the same meaning .
* CHECK condition
* NOT GRADE IN (5,22) on STAFF12
DISPLAY " TEST0310 "
DISPLAY " CHECK CONSTRAINTS "
DISPLAY " SQL with Integrity Enhancement section 6.8"
DISPLAY " - - - - - - - - - - - - - - - - - - - - - - - - "
DISPLAY " "
DISPLAY " INSERT INTO STAFF12"
DISPLAY " VALUES('E1','Thomas',0,'Deale');"
DISPLAY "code1 = SQLCODE;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF12"
DISPLAY " VALUES('E2','Dom',22,'Newyork');"
DISPLAY "code2 = SQLCODE;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF12"
DISPLAY " VALUES('E3','Susan',11,'Hawaii');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO :count1"
DISPLAY " FROM STAFF12;"
EXEC SQL DELETE FROM STAFF12 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF12
VALUES('E1','Thomas',0,'Deale') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code1
EXEC SQL INSERT INTO STAFF12
VALUES('E2','Tom',22,'Newyork') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code2
EXEC SQL INSERT INTO STAFF12
VALUES('E3','Susan',11,'Hawaii') END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL SELECT COUNT(*) INTO :count1
FROM STAFF12 END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " The correct answer is:"
DISPLAY " code1 < 0,code2 < 0,count1 = 1."
DISPLAY " Your answer is:"
DISPLAY " code1 = ", code1 ",code2 = ", code2
DISPLAY ",count1= ", count1
if (code1 NOT = 0 AND count1 = 1 ) then
EXEC SQL INSERT INTO TESTREPORT
VALUES('0310','pass','PCO') END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " *** pass *** "
else
EXEC SQL INSERT INTO TESTREPORT
VALUES('0310','fail','PCO') END-EXEC
ADD 1 TO errcnt
MOVE SQLCODE TO SQL-COD
DISPLAY " cdr004.pco *** fail *** "
END-IF
DISPLAY "================================================"
DISPLAY " "
EXEC SQL COMMIT WORK END-EXEC
MOVE SQLCODE TO SQL-COD
****************** END TEST0310 *****************************
******************** BEGIN TEST0311 *******************
*This test check the constraint NOT NULL in column
*definition constraint.
* CHECK condition
* NOT NULL in EMPNAME def. of STAFF15
* INSERT NULL INTO EMPNAME explicitly
DISPLAY " TEST0311 "
DISPLAY " CHECK CONSTRAINT "
DISPLAY " SQL with Integrity Enhancement section
- " 6.5,6.6"
DISPLAY " - - - - - - - - - - - - - - - - - - - - - "
DISPLAY " "
DISPLAY " INSERT INTO STAFF15"
DISPLAY " VALUES('E1','Alice',52,'Deale');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO:count1"
DISPLAY " FROM STAFF15;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF15"
DISPLAY " VALUES('E1',NULL,52,'Newyork');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO:count2"
DISPLAY " FROM STAFF15;"
MOVE 0 TO count1
MOVE 0 TO count2
EXEC SQL DELETE FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF15
VALUES('E1','Alice',52,'Deale') END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL SELECT COUNT(*) INTO :count1
FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF15
VALUES('E2',NULL,52,'Newyork') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code1
EXEC SQL SELECT COUNT(*) INTO :count2
FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " The correct answer is :"
DISPLAY " SQLCODE of second INSERT not equal to 0."
DISPLAY " count1 is 1"
DISPLAY " count2 is 1"
DISPLAY " Your answer is :"
DISPLAY " SQLCOD of second INSERT is ", code1
DISPLAY " count1 is ", count1
DISPLAY " count2 is ", count2
if (code1 NOT = 0 AND count1 = 1 AND count2 = 1)
then
EXEC SQL INSERT INTO TESTREPORT
VALUES('0311','pass','PCO') END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " *** pass *** "
else
EXEC SQL INSERT INTO TESTREPORT
VALUES('0311','fail','PCO') END-EXEC
ADD 1 TO errcnt
MOVE SQLCODE TO SQL-COD
DISPLAY " cdr004.pco *** fail *** "
END-IF
DISPLAY "================================================"
DISPLAY " "
EXEC SQL COMMIT WORK END-EXEC
MOVE SQLCODE TO SQL-COD
**************** END TEST 0311 **********
******************** BEGIN TEST0312 *******************
*This test checks NOT NULL in table definition con-
*straint.
* CHECK condition
* EMPNAME IS NOT NULL. on STAFF15
* INSERT VALUE INTO all columns except EMPNAME
DISPLAY " TEST0312 "
DISPLAY " CHECK CONSTRAINT "
DISPLAY " SQL with Integrity Enhancement section
- " 6.5,6.6"
DISPLAY " - - - - - - - - - - - - - - - - - - - - - "
DISPLAY " "
DISPLAY " INSERT INTO STAFF15"
DISPLAY " VALUES('E1','Alice',52,'Deale');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO :count1"
DISPLAY " FROM STAFF15;"
DISPLAY " "
DISPLAY " INSERT INTO STAFF15(EMPNUM,GRADE,CITY)"
DISPLAY " VALUES('E1',52,'Newyork');"
DISPLAY " "
DISPLAY " SELECT COUNT(*) INTO :count2"
DISPLAY " FROM STAFF15;"
COMPUTE count1 = -1
COMPUTE count2 = -1
EXEC SQL DELETE FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF15
VALUES('E1','Alice',52,'Deale') END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL SELECT COUNT(*) INTO :count1
FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
EXEC SQL INSERT INTO STAFF15(EMPNUM,GRADE,CITY)
VALUES('E2',52,'Newyork') END-EXEC
MOVE SQLCODE TO SQL-COD
MOVE SQLCODE TO code1
EXEC SQL SELECT COUNT(*) INTO :count2
FROM STAFF15 END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " The correct answer is :"
DISPLAY " SQLCODE of second INSERT not equal to 0."
DISPLAY " count1 is 1"
DISPLAY " count2 is 1"
DISPLAY " Your answer is :"
DISPLAY " SQLCOD of second INSERT is ", code1
DISPLAY " count1 is ", count1
DISPLAY " count2 is ", count2
if (code1 NOT = 0 AND count1 = 1 AND count2 = 1)
then
EXEC SQL INSERT INTO TESTREPORT
VALUES('0312','pass','PCO') END-EXEC
MOVE SQLCODE TO SQL-COD
DISPLAY " *** pass *** "
else
EXEC SQL INSERT INTO TESTREPORT
VALUES('0312','fail','PCO') END-EXEC
ADD 1 TO errcnt
MOVE SQLCODE TO SQL-COD
DISPLAY " cdr004.pco *** fail *** "
END-IF
DISPLAY "================================================"
DISPLAY " "
EXEC SQL COMMIT WORK END-EXEC
MOVE SQLCODE TO SQL-COD
**************** END TEST 0312 **********
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0
STOP RUN.
* **** Procedures for PERFORM statements
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