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Datei: cdr007.cob   Sprache: Cobol

       IDENTIFICATION DIVISION.
       PROGRAM-ID.  CDR007.
       ENVIRONMENT DIVISION.
       CONFIGURATION SECTION.
       SOURCE-COMPUTER.  xyz.
       OBJECT-COMPUTER.  xyz.
       DATA DIVISION.
       WORKING-STORAGE SECTION.


      * EMBEDDED COBOL (file "CDR007.PCO")  

      ****************************************************************
      *                                                              
      *                 COMMENT SECTION                              
      *                                                              
      * DATE 1989/04/07 EMBEDDED COBOL LANGUAGE                          
      * NIST SQL VALIDATION TEST SUITE V6.0
      *  DISCLAIMER:                                                  
      *  This program was written by employees of NIST to test SQL    
      *  implementations for conformance to the SQL standards.        
      *  NIST assumes no responsibility for any party's use of        
      *  this program.
      *                                                              
      * CDR007.PCO                                                    
      * WRITTEN BY: SUN DAJUN                                        
      * TRANSLATED AUTOMATICALLY FROM EMBEDDED C BY CHRIS SCHANZLE
      *                                                              
      *   THIS ROUTINE TESTS THE <CHECK> CONSTRAINT.                 
      *                                                              
      * REFERENCES                                                   
      *       AMERICAN NATIONAL STANDARD database language - SQL     
      *                          with Integrity Enhancement          
      *                                                              
      *            SECTION 6.8                                       
      *               <check constraint definition>::=               
      *                     CHECK (<search condition>)               
      ****************************************************************





           EXEC SQL BEGIN DECLARE SECTION END-EXEC
       01  count1 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
       01  count2 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
       01  uid PIC X(18).
       01  uidx PIC X(18).
           EXEC SQL END DECLARE SECTION END-EXEC
       01  SQLCODE PIC S9(9) COMP.
       01  errcnt PIC S9(4) DISPLAY SIGN LEADING SEPARATE.


       01  code1 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.
       01  code2 PIC S9(9) DISPLAY SIGN LEADING SEPARATE.

       01  SQL-COD PIC S9(9) DISPLAY SIGN LEADING SEPARATE.

      * date_time declaration *
       01  TO-DAY PIC 9(6).
       01  THE-TIME PIC 9(8).
    
       PROCEDURE DIVISION.
       P0.


           MOVE "SUN" TO uid
           CALL "AUTHID" USING uid
           MOVE "not logged in, not" TO uidx
           EXEC SQL SELECT 
                 USER INTO :uidx FROM SUN.ECCO END-EXEC
           if (uid NOT = uidx) then
             DISPLAY "ERROR: User " uid " expected."
             DISPLAY "User " uidx " connected."
             DISPLAY " "
             STOP RUN
           END-IF

           MOVE 0 TO errcnt
           DISPLAY
           "SQL Test Suite, V6.0, Embedded COBOL, cdr007.pco"
           DISPLAY " "
           DISPLAY
           "59-byte ID"
           DISPLAY "TEd Version #"
           DISPLAY " "
      * date_time print *
           ACCEPT TO-DAY FROM DATE
           ACCEPT THE-TIME FROM TIME
           DISPLAY "Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME
      ******************** BEGIN TEST0319 *******************
      *This procedure tests IN element in CHECK specification
      *Syntax Rules 6.3.8                                    
      *     CHECK condition                                  
      *             GRADE NOT IN (5,22)   on STAFF10         

           DISPLAY " TEST0319 "
           DISPLAY " CHECK CONSTRAINTS "
           DISPLAY " SQL with Integrity Enhancement section 6.8"
           DISPLAY " - - - - - - - - - - - - - - - - - - - - - - - - "
           DISPLAY  " "
           DISPLAY " INSERT INTO STAFF10"
           DISPLAY " VALUES('E3','Susan',11,'Hawaii');"
           DISPLAY  " "
           DISPLAY " UPDATE STAFF10"
           DISPLAY " SET GRADE = 5"
           DISPLAY " WHERE EMPNUM = 'E3';"
           DISPLAY  " "
           DISPLAY " SELECT COUNT(*) INTO :count1"
           DISPLAY " FROM STAFF10"
           DISPLAY " WHERE GRADE = 11;"
           EXEC SQL DELETE FROM STAFF10 END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL INSERT INTO STAFF10
             VALUES('E3','Susan',11,'Hawaii'END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL UPDATE STAFF10
             SET GRADE = 5
             WHERE EMPNUM = 'E3' END-EXEC
           MOVE SQLCODE TO SQL-COD
           MOVE SQLCODE TO code1
           EXEC SQL SELECT COUNT(*) INTO :count1
             FROM STAFF10
             WHERE GRADE = 11 END-EXEC
           MOVE SQLCODE TO SQL-COD
           DISPLAY " The correct answer is:"
           DISPLAY " code1 < 0,count = 1."
           DISPLAY " Your answer is:"
           DISPLAY " code1 = ", code1
           DISPLAY ",count1= ", count1
           if (code1  <  0  AND  count1  =  1 ) then
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0319','pass','PCO'END-EXEC
             MOVE SQLCODE TO SQL-COD
             DISPLAY " *** pass *** "
           else
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0319','fail','PCO'END-EXEC
             ADD 1 TO errcnt
             MOVE SQLCODE TO SQL-COD
             DISPLAY " cdr007.pco *** fail *** "
           END-IF
           DISPLAY "================================================"

           DISPLAY  " "
           EXEC SQL COMMIT WORK END-EXEC
           MOVE SQLCODE TO SQL-COD
      ****************** END TEST0319 *****************************







      ******************** BEGIN TEST0320 ******************
      *This procedure tests CHECK specification on two     
      *columns with AND.                                   
      *     CHECK condition                                
      *          GRADE NOT IN (5,22) AND EMPNAME LIKE 'T%' 

           DISPLAY " TEST0320 "
           DISPLAY " CHECK CONSTRAINTS "
           DISPLAY " SQL with Integrity Enhancement section 6.8"
           DISPLAY " - - - - - - - - - - - - - - - - - - - - - - - - "
           DISPLAY  " "
           DISPLAY " INSERT INTO STAFF11"
           DISPLAY " VALUES('E3','Susan',11,'Hawaii');"
           DISPLAY  " "
           DISPLAY " UPDATE STAFF11"
           DISPLAY " SET GRADE = 5"
           DISPLAY " WHERE EMPNUM = 'E3';"
           DISPLAY  " "
           DISPLAY " UPDATE STAFF11"
           DISPLAY " SET EMPNAME = 'Tom'"
           DISPLAY " WHERE EMPNUM = 'E3';"
           DISPLAY  " "
           DISPLAY " SELECT COUNT(*) INTO :count1"
           DISPLAY " FROM STAFF11"
           DISPLAY " WHERE EMPNAME = 'Susan' AND GRADE = 11;"
           EXEC SQL DELETE FROM STAFF11 END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL INSERT INTO STAFF11
             VALUES('E3','Susan',11,'Hawaii'END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL UPDATE STAFF11
             SET GRADE = 5
             WHERE EMPNUM = 'E3' END-EXEC
           MOVE SQLCODE TO SQL-COD
           MOVE SQLCODE TO code1
           EXEC SQL UPDATE STAFF11
             SET EMPNAME = 'Tom'
             WHERE EMPNUM = 'E3' END-EXEC
           MOVE SQLCODE TO SQL-COD
           MOVE SQLCODE TO code2
           EXEC SQL SELECT COUNT(*) INTO :count1
             FROM STAFF11
             WHERE EMPNAME = 'Susan' AND GRADE = 11 END-EXEC
           MOVE SQLCODE TO SQL-COD
           DISPLAY " The correct answer is:"
           DISPLAY " code1 < 0,code2 < 0,count = 1."
           DISPLAY " Your answer is:"
           DISPLAY " code1 = ", code1 ",code2 = ", code2
           DISPLAY ",count1= ", count1
           if (code1  <  0  AND  code2  <  0  AND  count1  =  1 ) then
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0320','pass','PCO'END-EXEC
             MOVE SQLCODE TO SQL-COD
             DISPLAY " *** pass *** "
           else
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0320','fail','PCO'END-EXEC
             ADD 1 TO errcnt
             MOVE SQLCODE TO SQL-COD
             DISPLAY " cdr007.pco *** fail *** "
           END-IF
           DISPLAY "================================================"

           DISPLAY  " "
           EXEC SQL COMMIT WORK END-EXEC
           MOVE SQLCODE TO SQL-COD
      ****************** END TEST0320 *****************************



      ******************** BEGIN TEST0321 *******************
      *This procedure tests if x NOT IN and NOT x IN of the
      *CHECK specification has the same meaning .           
      *          CHECK condition                            
      *              NOT GRADE IN (5,22) on STAFF12         

           DISPLAY " TEST0321 "
           DISPLAY " CHECK CONSTRAINTS "
           DISPLAY " SQL with Integrity Enhancement section 6.8"
           DISPLAY " - - - - - - - - - - - - - - - - - - - - - - - - "
           DISPLAY  " "
           DISPLAY " INSERT INTO STAFF12"
           DISPLAY " VALUES('E3','Susan',11,'Hawaii');"
           DISPLAY  " "
           DISPLAY " UPDATE STAFF12"
           DISPLAY " SET GRADE = 5"
           DISPLAY " WHERE EMPNUM = 'E3';"
           DISPLAY  " "
           DISPLAY " SELECT COUNT(*) INTO :count1"
           DISPLAY " FROM STAFF12"
           DISPLAY " WHERE GRADE = 11;"
           EXEC SQL DELETE FROM STAFF12 END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL INSERT INTO STAFF12
             VALUES('E3','Susan',11,'Hawaii'END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL UPDATE STAFF12
             SET GRADE = 5
             WHERE EMPNUM = 'E3' END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL SELECT COUNT(*) INTO :count1
             FROM STAFF12
             WHERE GRADE = 11 END-EXEC
           MOVE SQLCODE TO SQL-COD
           DISPLAY " The correct answer is:"
           DISPLAY " code1 < 0,count = 1."
           DISPLAY " Your answer is:"
           DISPLAY " code1 = ", code1
           DISPLAY ",count1= ", count1
           if (code1  <  0  AND  count1  =  1 ) then
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0321','pass','PCO'END-EXEC
             MOVE SQLCODE TO SQL-COD
             DISPLAY " *** pass *** "
           else
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0321','fail','PCO'END-EXEC
             ADD 1 TO errcnt
             MOVE SQLCODE TO SQL-COD
             DISPLAY " cdr007.pco *** fail *** "
           END-IF
           DISPLAY "================================================"

           DISPLAY  " "
           EXEC SQL COMMIT WORK END-EXEC
           MOVE SQLCODE TO SQL-COD
      ****************** END TEST0321 *****************************



      ******************** BEGIN TEST0322 *******************
      *This test check the constraint NOT NULL in column    
      *definition constraint.                               
      *      CHECK condition                                
      *            NOT NULL   in EMPNAME def. of STAFF15    
      *    INSERT NULL INTO EMPNAME explicitly              


           DISPLAY " TEST0322 "
           DISPLAY " CHECK CONSTRAINT "
           DISPLAY " SQL with Integrity Enhancement section
      -    " 6.5,6.6"
           DISPLAY " - - - - - - - - - - - - - - - - - - - - - "
           DISPLAY  " "
           DISPLAY " INSERT INTO STAFF15"
           DISPLAY " VALUES('E1','Alice',52,'Deale');"
           DISPLAY  " "
           DISPLAY " UPDATE STAFF15"
           DISPLAY " SET EMPNAME = NULL"
           DISPLAY " WHERE EMPNUM = 'E1';"
           DISPLAY  " "
           DISPLAY " SELECT COUNT(*) INTO:count1"
           DISPLAY " FROM STAFF15"
           DISPLAY " WHERE EMPNAME = 'Alice';"
           MOVE 0 TO count1
           EXEC SQL DELETE FROM STAFF15 END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL INSERT INTO STAFF15
             VALUES('E1','Alice',52,'Deale'END-EXEC
           MOVE SQLCODE TO SQL-COD
           EXEC SQL UPDATE STAFF15
             SET EMPNAME = NULL
             WHERE EMPNUM = 'E1' END-EXEC
           MOVE SQLCODE TO SQL-COD
           MOVE SQLCODE TO code1
           EXEC SQL SELECT COUNT(*) INTO:count1
             FROM STAFF15
             WHERE EMPNAME = 'Alice' END-EXEC
           MOVE SQLCODE TO SQL-COD
           DISPLAY " The correct answer is :"
           DISPLAY " code1 is less than 0."
           DISPLAY " count1 is 1"
           DISPLAY " Your answer is :"
           DISPLAY " code1 is ", code1
           DISPLAY " count1 is ", count1
           if (code1  <  0  AND  count1  =  1) then
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0322','pass','PCO'END-EXEC
             MOVE SQLCODE TO SQL-COD
             DISPLAY " *** pass *** "
           else
             EXEC SQL INSERT INTO TESTREPORT
               VALUES('0322','fail','PCO'END-EXEC
             ADD 1 TO errcnt
             MOVE SQLCODE TO SQL-COD
             DISPLAY " cdr007.pco *** fail *** "
           END-IF
           DISPLAY "================================================"

           DISPLAY  " "
           EXEC SQL COMMIT WORK END-EXEC
           MOVE SQLCODE TO SQL-COD
      **************** END TEST 0322 **********







      **** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0
           STOP RUN.

      *    ****  Procedures for PERFORM statements

¤ Dauer der Verarbeitung: 0.20 Sekunden  (vorverarbeitet)  ¤





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