def regex_opt_inner(strings, open_paren): """Return a regex that matches any string in the sorted list of strings."""
close_paren = open_paren and')'or'' # print strings, repr(open_paren) ifnot strings: # print '-> nothing left' return''
first = strings[0] if len(strings) == 1: # print '-> only 1 string' return open_paren + escape(first) + close_paren ifnot first: # print '-> first string empty' return open_paren + regex_opt_inner(strings[1:], '(?:') \
+ '?' + close_paren if len(first) == 1: # multiple one-char strings? make a charset
oneletter = []
rest = [] for s in strings: if len(s) == 1:
oneletter.append(s) else:
rest.append(s) if len(oneletter) > 1: # do we have more than one oneletter string? if rest: # print '-> 1-character + rest' return open_paren + regex_opt_inner(rest, '') + '|' \
+ make_charset(oneletter) + close_paren # print '-> only 1-character' return open_paren + make_charset(oneletter) + close_paren
prefix = commonprefix(strings) if prefix:
plen = len(prefix) # we have a prefix for all strings # print '-> prefix:', prefix return open_paren + escape(prefix) \
+ regex_opt_inner([s[plen:] for s in strings], '(?:') \
+ close_paren # is there a suffix?
strings_rev = [s[::-1] for s in strings]
suffix = commonprefix(strings_rev) if suffix:
slen = len(suffix) # print '-> suffix:', suffix[::-1] return open_paren \
+ regex_opt_inner(sorted(s[:-slen] for s in strings), '(?:') \
+ escape(suffix[::-1]) + close_paren # recurse on common 1-string prefixes # print '-> last resort' return open_paren + \ '|'.join(regex_opt_inner(list(group[1]), '') for group in groupby(strings, lambda s: s[0] == first[0])) \
+ close_paren
def regex_opt(strings, prefix='', suffix=''): """Return a compiled regex that matches any string in the given list.
The strings to match must be literal strings, not regexes. They will be
regex-escaped.
*prefix* and *suffix* are pre- and appended to the final regex. """
strings = sorted(strings) return prefix + regex_opt_inner(strings, '(') + suffix
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