* Standard COBOL (file "CDR007.SCO") calling SQL * procedures in file "CDR007.MCO"
**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 STANDARD COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR007.SCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED COBOL BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE <CHECK> CONSTRAINT. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.8 * <check constraint definition>::= * CHECK (<search condition>) ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx CALL"AUTHCK"USING SQLCODE uidx MOVE SQLCODE TO SQL-COD if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Module COBOL, cdr007.sco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME ******************** BEGIN TEST0319 ******************* *This procedure tests IN element in CHECK specification *Syntax Rules 6.3.8 * CHECK condition * GRADE NOT IN (5,22) on STAFF10
DISPLAY" TEST0319 " DISPLAY" CHECK CONSTRAINTS " DISPLAY" SQL with Integrity Enhancement section 6.8" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF10" DISPLAY" VALUES('E3','Susan',11,'Hawaii');" DISPLAY" " DISPLAY" UPDATE STAFF10" DISPLAY" SET GRADE = 5" DISPLAY" WHERE EMPNUM = 'E3';" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF10" DISPLAY" WHERE GRADE = 11;" * EXEC SQL DELETE FROM STAFF10; CALL"SUB1"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF10 * VALUES('E3','Susan',11,'Hawaii') END-EXEC CALL"SUB2"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF10 * SET GRADE = 5 * WHERE EMPNUM = 'E3' END-EXEC CALL"SUB3"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM STAFF10 * WHERE GRADE = 11 END-EXEC CALL"SUB4"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is:" DISPLAY" code1 < 0,count = 1." DISPLAY" Your answer is:" DISPLAY" code1 = ", code1 DISPLAY",count1= ", count1 if (code1 < 0 AND count1 = 1 ) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0319','pass','MCO') END-EXEC CALL"SUB5"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0319','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB6"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr007.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB7"USING SQLCODE MOVE SQLCODE TO SQL-COD ****************** END TEST0319 *****************************
******************** BEGIN TEST0320 ****************** *This procedure tests CHECK specification on two *columns with AND. * CHECK condition * GRADE NOT IN (5,22) AND EMPNAME LIKE 'T%'
DISPLAY" TEST0320 " DISPLAY" CHECK CONSTRAINTS " DISPLAY" SQL with Integrity Enhancement section 6.8" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF11" DISPLAY" VALUES('E3','Susan',11,'Hawaii');" DISPLAY" " DISPLAY" UPDATE STAFF11" DISPLAY" SET GRADE = 5" DISPLAY" WHERE EMPNUM = 'E3';" DISPLAY" " DISPLAY" UPDATE STAFF11" DISPLAY" SET EMPNAME = 'Tom'" DISPLAY" WHERE EMPNUM = 'E3';" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF11" DISPLAY" WHERE EMPNAME = 'Susan' AND GRADE = 11;" * EXEC SQL DELETE FROM STAFF11; CALL"SUB8"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF11 * VALUES('E3','Susan',11,'Hawaii') END-EXEC CALL"SUB9"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF11 * SET GRADE = 5 * WHERE EMPNUM = 'E3' END-EXEC CALL"SUB10"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL UPDATE STAFF11 * SET EMPNAME = 'Tom' * WHERE EMPNUM = 'E3' END-EXEC CALL"SUB11"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM STAFF11 * WHERE EMPNAME = 'Susan' AND GRADE = 11 END-EXEC CALL"SUB12"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is:" DISPLAY" code1 < 0,code2 < 0,count = 1." DISPLAY" Your answer is:" DISPLAY" code1 = ", code1 ",code2 = ", code2 DISPLAY",count1= ", count1 if (code1 < 0 AND code2 < 0 AND count1 = 1 ) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0320','pass','MCO') END-EXEC CALL"SUB13"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0320','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB14"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr007.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB15"USING SQLCODE MOVE SQLCODE TO SQL-COD ****************** END TEST0320 *****************************
******************** BEGIN TEST0321 ******************* *This procedure tests if x NOT IN and NOT x IN of the *CHECK specification has the same meaning . * CHECK condition * NOT GRADE IN (5,22) on STAFF12
DISPLAY" TEST0321 " DISPLAY" CHECK CONSTRAINTS " DISPLAY" SQL with Integrity Enhancement section 6.8" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF12" DISPLAY" VALUES('E3','Susan',11,'Hawaii');" DISPLAY" " DISPLAY" UPDATE STAFF12" DISPLAY" SET GRADE = 5" DISPLAY" WHERE EMPNUM = 'E3';" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM STAFF12" DISPLAY" WHERE GRADE = 11;" * EXEC SQL DELETE FROM STAFF12; CALL"SUB16"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF12 * VALUES('E3','Susan',11,'Hawaii') END-EXEC CALL"SUB17"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF12 * SET GRADE = 5 * WHERE EMPNUM = 'E3' END-EXEC CALL"SUB18"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM STAFF12 * WHERE GRADE = 11 END-EXEC CALL"SUB19"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is:" DISPLAY" code1 < 0,count = 1." DISPLAY" Your answer is:" DISPLAY" code1 = ", code1 DISPLAY",count1= ", count1 if (code1 < 0 AND count1 = 1 ) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0321','pass','MCO') END-EXEC CALL"SUB20"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0321','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB21"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr007.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB22"USING SQLCODE MOVE SQLCODE TO SQL-COD ****************** END TEST0321 *****************************
******************** BEGIN TEST0322 ******************* *This test check the constraint NOT NULL in column *definition constraint. * CHECK condition * NOT NULL in EMPNAME def. of STAFF15 * INSERT NULL INTO EMPNAME explicitly
DISPLAY" TEST0322 " DISPLAY" CHECK CONSTRAINT " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO STAFF15" DISPLAY" VALUES('E1','Alice',52,'Deale');" DISPLAY" " DISPLAY" UPDATE STAFF15" DISPLAY" SET EMPNAME = NULL" DISPLAY" WHERE EMPNUM = 'E1';" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM STAFF15" DISPLAY" WHERE EMPNAME = 'Alice';" MOVE 0 TO count1 * EXEC SQL DELETE FROM STAFF15; CALL"SUB23"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO STAFF15 * VALUES('E1','Alice',52,'Deale') END-EXEC CALL"SUB24"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE STAFF15 * SET EMPNAME = NULL * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB25"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM STAFF15 * WHERE EMPNAME = 'Alice' END-EXEC CALL"SUB26"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is less than 0." DISPLAY" count1 is 1" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" count1 is ", count1 if (code1 < 0 AND count1 = 1) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0322','pass','MCO') END-EXEC CALL"SUB27"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0322','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB28"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr007.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB29"USING SQLCODE MOVE SQLCODE TO SQL-COD **************** END TEST 0322 **********
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
¤ Dauer der Verarbeitung: 0.11 Sekunden
(vorverarbeitet)
¤
Die Informationen auf dieser Webseite wurden
nach bestem Wissen sorgfältig zusammengestellt. Es wird jedoch weder Vollständigkeit, noch Richtigkeit,
noch Qualität der bereit gestellten Informationen zugesichert.
Bemerkung:
Die farbliche Syntaxdarstellung ist noch experimentell.