If $L$ is a descendant of 6.173 of order $p^{7}$ then the commutator
structure of $L$ is the same as that of one of the $p+2$ algebras with
presentations 7.106 and 7.107 from the list of nilpotent Lie algebras of
dimension 7 over $\mathbb{Z}_{p}$. So we can assume that $L$ has the
following commutator relations \[
ca=bab,\,cb=\omega baa,\,baab=\lambda baaa,\,babb=\mu baaa \]%
for some parameters $\lambda ,\mu $.
If we let $C=\langle c\rangle +L^{2}$ then, if $a^{\prime },b^{\prime
},c^{\prime }$ are the images of $a,b,c$ under an automorphism of $L$, we
have \begin{eqnarray*}
a^{\prime } &=&\alpha a+\beta b\func{mod}C, \\
b^{\prime } &=&\pm (\omega\beta a+\alpha b)\func{mod}C, \\
c^{\prime } &=&(\alpha ^{2}-\omega\beta ^{2})c\func{mod}L^{3} \end{eqnarray*}%
for some $\alpha ,\beta $ which are not both zero. It follows that \begin{eqnarray*} \lbrack b^{\prime },a^{\prime },a^{\prime },a^{\prime }] &=&\pm (\alpha
^{2}-\omega\beta ^{2})(\alpha ^{2}+2\alpha\beta\lambda +\beta ^{2}\mu
)[b,a,a,a], \\ \lbrack b^{\prime },a^{\prime },a^{\prime },b^{\prime }] &=&(\alpha
^{2}-\omega\beta ^{2})(\omega\alpha\beta +\alpha ^{2}\lambda +\omega \beta ^{2}\lambda +\alpha\beta\mu )[b,a,a,a], \\ \lbrack b^{\prime },a^{\prime },b^{\prime },b^{\prime }] &=&\pm (\alpha
^{2}-\omega\beta ^{2})(\omega ^{2}\beta ^{2}+2\omega\alpha\beta\lambda
+\alpha ^{2}\mu )[b,a,a,a]. \end{eqnarray*}%
So provided $\alpha ^{2}+2\alpha\beta\lambda +\beta ^{2}\mu\neq 0$ the
effect of this automorphism is to transform the parameters $\lambda ,\mu $ to% \[ \frac{\pm (\omega\alpha\beta +\alpha ^{2}\lambda +\omega\beta ^{2}\lambda
+\alpha\beta\mu )}{\alpha ^{2}+2\alpha\beta\lambda +\beta ^{2}\mu },\;% \frac{\omega ^{2}\beta ^{2}+2\omega\alpha\beta\lambda +\alpha ^{2}\mu }{% \alpha ^{2}+2\alpha\beta\lambda +\beta ^{2}\mu }. \]%
There are $p+2$ orbits of pairs $\lambda ,\mu $ under this action.
We pick a set representative pairs $\lambda ,\mu $ for these orbits, and get
the following presentations for the descendants of 6.173 of order $p^{7}$:
For each pair $\lambda ,\mu $ we compute the subgroup of the automorphism
group which fixes $\lambda ,\mu $, and compute its action on the parameters $%
y,z,\dot{t}$. It turns out that we need to treat the pair $\lambda =\mu =0$
separately from the other pairs.
If $\lambda =\mu =0$. Then the subgroup of the automorphism group we need to
consider maps $a,b,c$ to $a^{\prime },b^{\prime },c^{\prime }$ where \begin{eqnarray*}
a^{\prime } &=&\alpha a, \\
b^{\prime } &=&\pm\alpha b+\varepsilon c, \\
c^{\prime } &=&\alpha ^{2}c, \end{eqnarray*}%
with $b^{\prime }a^{\prime }a^{\prime }a^{\prime }=\pm\alpha ^{4}baaa$.
In all other cases we can assume that if $pc\neq 0$ then $pa=pb=0$. A \textsc{Magma} program to compute a set of representatives for the
parameters $\lambda ,\mu ,y,z,t$ is given in notes6.173.m.
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