/* Generate a "word" with platform-dependent size whose bytes all contain the * value 'b'.
*/ static forceinline size_t repeat_byte(u8 b)
{
size_t v;
v = b;
v |= v << 8;
v |= v << 16;
v |= v << ((WORDBYTES == 8) ? 32 : 0); return v;
}
/* Structure that encapsulates a block of in-memory data being interpreted as a * stream of bits, optionally with interwoven literal bytes. Bits are assumed * to be stored in little endian 16-bit coding units, with the bits ordered high * to low.
*/ struct input_bitstream {
/* Bits that have been read from the input buffer. The bits are * left-justified; the next bit is always bit 31.
*/
u32 bitbuf;
/* Number of bits currently held in @bitbuf. */
u32 bitsleft;
/* Pointer to the next byte to be retrieved from the input buffer. */ const u8 *next;
/* Pointer to just past the end of the input buffer. */ const u8 *end;
};
/* Initialize a bitstream to read from the specified input buffer. */ static forceinline void init_input_bitstream(struct input_bitstream *is, constvoid *buffer, u32 size)
{
is->bitbuf = 0;
is->bitsleft = 0;
is->next = buffer;
is->end = is->next + size;
}
/* Ensure the bit buffer variable for the bitstream contains at least @num_bits * bits. Following this, bitstream_peek_bits() and/or bitstream_remove_bits() * may be called on the bitstream to peek or remove up to @num_bits bits. Note * that @num_bits must be <= 16.
*/ static forceinline void bitstream_ensure_bits(struct input_bitstream *is,
u32 num_bits)
{ if (is->bitsleft < num_bits) { if (is->end - is->next >= 2) {
is->bitbuf |= (u32)get_unaligned_le16(is->next)
<< (16 - is->bitsleft);
is->next += 2;
}
is->bitsleft += 16;
}
}
/* Return the next @num_bits bits from the bitstream, without removing them. * There must be at least @num_bits remaining in the buffer variable, from a * previous call to bitstream_ensure_bits().
*/ static forceinline u32
bitstream_peek_bits(conststruct input_bitstream *is, const u32 num_bits)
{ return (is->bitbuf >> 1) >> (sizeof(is->bitbuf) * 8 - num_bits - 1);
}
/* Remove @num_bits from the bitstream. There must be at least @num_bits * remaining in the buffer variable, from a previous call to * bitstream_ensure_bits().
*/ static forceinline void
bitstream_remove_bits(struct input_bitstream *is, u32 num_bits)
{
is->bitbuf <<= num_bits;
is->bitsleft -= num_bits;
}
/* Remove and return @num_bits bits from the bitstream. There must be at least * @num_bits remaining in the buffer variable, from a previous call to * bitstream_ensure_bits().
*/ static forceinline u32
bitstream_pop_bits(struct input_bitstream *is, u32 num_bits)
{
u32 bits = bitstream_peek_bits(is, num_bits);
/* Read and return the next @num_bits bits from the bitstream. */ static forceinline u32
bitstream_read_bits(struct input_bitstream *is, u32 num_bits)
{
bitstream_ensure_bits(is, num_bits); return bitstream_pop_bits(is, num_bits);
}
/* Read and return the next literal byte embedded in the bitstream. */ static forceinline u8
bitstream_read_byte(struct input_bitstream *is)
{ if (unlikely(is->end == is->next)) return 0; return *is->next++;
}
/* Read and return the next 16-bit integer embedded in the bitstream. */ static forceinline u16
bitstream_read_u16(struct input_bitstream *is)
{
u16 v;
if (unlikely(is->end - is->next < 2)) return 0;
v = get_unaligned_le16(is->next);
is->next += 2; return v;
}
/* Read and return the next 32-bit integer embedded in the bitstream. */ static forceinline u32
bitstream_read_u32(struct input_bitstream *is)
{
u32 v;
if (unlikely(is->end - is->next < 4)) return 0;
v = get_unaligned_le32(is->next);
is->next += 4; return v;
}
/* Read into @dst_buffer an array of literal bytes embedded in the bitstream. * Return either a pointer to the byte past the last written, or NULL if the * read overflows the input buffer.
*/ static forceinline void *bitstream_read_bytes(struct input_bitstream *is, void *dst_buffer, size_t count)
{ if ((size_t)(is->end - is->next) < count) return NULL;
memcpy(dst_buffer, is->next, count);
is->next += count; return (u8 *)dst_buffer + count;
}
/* Align the input bitstream on a coding-unit boundary. */ static forceinline void bitstream_align(struct input_bitstream *is)
{
is->bitsleft = 0;
is->bitbuf = 0;
}
/* Reads and returns the next Huffman-encoded symbol from a bitstream. If the * input data is exhausted, the Huffman symbol is decoded as if the missing bits * are all zeroes.
*/ static forceinline u32 read_huffsym(struct input_bitstream *istream, const u16 decode_table[],
u32 table_bits,
u32 max_codeword_len)
{
u32 entry;
u32 key_bits;
bitstream_ensure_bits(istream, max_codeword_len);
/* Index the decode table by the next table_bits bits of the input. */
key_bits = bitstream_peek_bits(istream, table_bits);
entry = decode_table[key_bits]; if (entry < 0xC000) { /* Fast case: The decode table directly provided the * symbol and codeword length. The low 11 bits are the * symbol, and the high 5 bits are the codeword length.
*/
bitstream_remove_bits(istream, entry >> 11); return entry & 0x7FF;
} /* Slow case: The codeword for the symbol is longer than * table_bits, so the symbol does not have an entry * directly in the first (1 << table_bits) entries of the * decode table. Traverse the appropriate binary tree * bit-by-bit to decode the symbol.
*/
bitstream_remove_bits(istream, table_bits); do {
key_bits = (entry & 0x3FFF) + bitstream_pop_bits(istream, 1);
} while ((entry = decode_table[key_bits]) >= 0xC000); return entry;
}
/* * Copy an LZ77 match at (dst - offset) to dst. * * The length and offset must be already validated --- that is, (dst - offset) * can't underrun the output buffer, and (dst + length) can't overrun the output * buffer. Also, the length cannot be 0. * * @bufend points to the byte past the end of the output buffer. This function * won't write any data beyond this position. * * Returns dst + length.
*/ static forceinline u8 *lz_copy(u8 *dst, u32 length, u32 offset, const u8 *bufend,
u32 min_length)
{ const u8 *src = dst - offset;
/* * Try to copy one machine word at a time. On i386 and x86_64 this is * faster than copying one byte at a time, unless the data is * near-random and all the matches have very short lengths. Note that * since this requires unaligned memory accesses, it won't necessarily * be faster on every architecture. * * Also note that we might copy more than the length of the match. For * example, if a word is 8 bytes and the match is of length 5, then * we'll simply copy 8 bytes. This is okay as long as we don't write * beyond the end of the output buffer, hence the check for (bufend - * end >= WORDBYTES - 1).
*/ #ifdef FAST_UNALIGNED_ACCESS
u8 * const end = dst + length;
if (bufend - end >= (ptrdiff_t)(WORDBYTES - 1)) {
if (offset >= WORDBYTES) { /* The source and destination words don't overlap. */
/* To improve branch prediction, one iteration of this * loop is unrolled. Most matches are short and will * fail the first check. But if that check passes, then * it becomes increasing likely that the match is long * and we'll need to continue copying.
*/
if (dst < end) { do {
copy_unaligned_word(src, dst);
src += WORDBYTES;
dst += WORDBYTES;
} while (dst < end);
} return end;
} elseif (offset == 1) {
/* Offset 1 matches are equivalent to run-length * encoding of the previous byte. This case is common * if the data contains many repeated bytes.
*/
size_t v = repeat_byte(*(dst - 1));
do {
put_unaligned(v, (size_t *)dst);
src += WORDBYTES;
dst += WORDBYTES;
} while (dst < end); return end;
} /* * We don't bother with special cases for other 'offset < * WORDBYTES', which are usually rarer than 'offset == 1'. Extra * checks will just slow things down. Actually, it's possible * to handle all the 'offset < WORDBYTES' cases using the same * code, but it still becomes more complicated doesn't seem any * faster overall; it definitely slows down the more common * 'offset == 1' case.
*/
} #endif/* FAST_UNALIGNED_ACCESS */
/* Fall back to a bytewise copy. */
if (min_length >= 2) {
*dst++ = *src++;
length--;
} if (min_length >= 3) {
*dst++ = *src++;
length--;
} do {
*dst++ = *src++;
} while (--length);
return dst;
}
#endif/* _LINUX_NTFS3_LIB_DECOMPRESS_COMMON_H */
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