* Standard COBOL (file "CDR019.SCO") calling SQL * procedures in file "CDR019.MCO"
**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 STANDARD COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR019.SCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED COBOL BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE REFERENTIAL INTEGRITY CONSTRAINT FOR * SQL. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.7 <referential constraint definition> * <referential constraint definition>::= * FOREIGN KEY (<referencing columns>) * <references specification> * <references specification>::= * REFERENCES <referenced table and columns> * <referencing columns>::= * <reference column list> * <refereced table and columns>::= * <table name>((<reference column list> * <reference column list>::= * <column name>({,<column name>}...) * ****************************************************************
MOVE"SUN"TO uid CALL"AUTHID"USING uid MOVE"not logged in, not"TO uidx CALL"AUTHCK"USING SQLCODE uidx MOVE SQLCODE TO SQL-COD if (uid NOT = uidx) then DISPLAY"ERROR: User " uid " expected." DISPLAY"User " uidx " connected." DISPLAY" " STOPRUN END-IF
MOVE 0 TO errcnt DISPLAY "SQL Test Suite, V6.0, Module COBOL, cdr019.sco" DISPLAY" " DISPLAY "59-byte ID" DISPLAY"TEd Version #" DISPLAY" " * date_time print * ACCEPT TO-DAY FROMDATE ACCEPT THE-TIME FROMTIME DISPLAY"Date run YYMMDD: " TO-DAY " at hhmmssff: " THE-TIME ******************** BEGIN TEST0365 *******************
* insert row into FOREIGN KEY TABLE EMP, check * referential integrity. TABLE EMP is also a PRIMARY * KEY TABLE to EXPERIENCE TABLE
DISPLAY" TEST0365 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (41,'Tom','China Architecture'," DISPLAY" 20,'Architecture',040553);" DISPLAY" " DISPLAY" INSERT INTO DEPT VALUES" DISPLAY" (20,'Architecture','Richard');" DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (41,'Tom','China Architecture'," DISPLAY" 20,'Architecture',040553);" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1 FROM EMP" DISPLAY" WHERE ENO = 41;" DISPLAY" " COMPUTE count1 = -1 * EXEC SQL INSERT INTO EMP VALUES * (41,'Tom','China Architecture', * 20,'Architecture',040553) END-EXEC CALL"SUB1"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL INSERT INTO DEPT VALUES * (20,'Architecture','Richard') END-EXEC CALL"SUB2"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL INSERT INTO EMP VALUES * (41,'Tom','China Architecture', * 20,'Architecture',040553) END-EXEC CALL"SUB3"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 * EXEC SQL SELECT COUNT(*) INTO :count1 FROM EMP * WHERE ENO = 41 END-EXEC CALL"SUB4"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD * EXEC SQL ROLLBACK WORK; CALL"SUB5"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is less than 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 1" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND count1 = 1 AND code2 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0365','pass','MCO') END-EXEC CALL"SUB6"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0365','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB7"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB8"USING SQLCODE MOVE SQLCODE TO SQL-COD **************** END TEST 0365 **********
******************** BEGIN TEST0366 *******************
* insert row into PRIMARY KEY TABLE EMP, check * referential integrity. TABLE EMP is also a FOREIGN * KEY TABLE to TABLE DEPT
DISPLAY" TEST0366 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" DELETE FROM EXPERIENCE" DISPLAY" WHERE EXP_NAME = 'Tom' AND BTH_DATE=040523;" DISPLAY" " DISPLAY" DELETE FROM EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1 FROM EMP" DISPLAY" WHERE ENO = 21;" COMPUTE count1 = -1 * EXEC SQL DELETE FROM EMP * WHERE ENO = 21 END-EXEC CALL"SUB9"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL DELETE FROM EXPERIENCE * WHERE EXP_NAME = 'Tom' AND BTH_DATE = 040523 END-EXEC CALL"SUB10"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL DELETE FROM EMP * WHERE ENO = 21 END-EXEC CALL"SUB11"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 * EXEC SQL SELECT COUNT(*) INTO :count1 FROM EMP * WHERE ENO = 21 END-EXEC CALL"SUB12"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD * EXEC SQL ROLLBACK WORK; CALL"SUB13"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 NOT = 0 AND count1 = 0 AND code2 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0366','pass','MCO') END-EXEC CALL"SUB14"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0366','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB15"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB16"USING SQLCODE MOVE SQLCODE TO SQL-COD **************** END TEST 0366 **********
******************** BEGIN TEST0367 *******************
* Update middle table, check the effect of this table * as both PRIMARY TABLE (to upper level) and FOREIGN * TABLE (to lower level).
DISPLAY" TEST0367 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET ENAME = 'Thomas'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET DNAME = 'Agriculture'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET DNAME = 'Education'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM EMP" DISPLAY" WHERE DNO = 12 AND DNAME = 'Education'" DISPLAY" AND ENO = 21 AND ENAME = 'Tom';" DISPLAY" " COMPUTE count1 = -1 * EXEC SQL UPDATE EMP * SET ENAME = 'Thomas' * WHERE ENO = 21 END-EXEC CALL"SUB17"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL UPDATE EMP * SET DNAME = 'Agriculture' * WHERE ENO = 21 END-EXEC CALL"SUB18"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 * EXEC SQL UPDATE EMP * SET DNAME = 'Education' * WHERE ENO = 21 END-EXEC CALL"SUB19"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM EMP * WHERE DNO = 12 AND DNAME = 'Education' * AND ENO = 21 AND ENAME = 'Tom' END-EXEC CALL"SUB20"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD * EXEC SQL ROLLBACK WORK; CALL"SUB21"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is not equal to 0." DISPLAY" count1 is 1" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND code2 < 0 AND count1 = 1) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0367','pass','MCO') END-EXEC CALL"SUB22"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0367','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB23"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB24"USING SQLCODE MOVE SQLCODE TO SQL-COD ************************ END TEST0367 ************************
******************** BEGIN TEST0368 ******************* *The employee Tom in EMP, his name is changed into *Thomas, this will affect the integrity. DISPLAY" TEST0368 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" UPDATE EMP" DISPLAY" SET ENAME = 'Thomas'" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" INSERT INTO EMP VALUES" DISPLAY" (30,'Thomas','Languages & Operating
- " System'," DISPLAY" 12,'Computer',040523);" DISPLAY" " DISPLAY" UPDATE EXPERIENCE" DISPLAY" SET EXP_NAME = 'Thomas'" DISPLAY" WHERE EXP_NAME = 'Tom' AND BTH_DATE=040523;" DISPLAY" " DISPLAY" DELETE EMP" DISPLAY" WHERE ENO = 21;" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO :count1" DISPLAY" FROM EMP" DISPLAY" WHERE DNO = 12 AND ENO = 21 " DISPLAY" AND ENAME = 'Tom';" DISPLAY" " COMPUTE count1 = -1 * EXEC SQL UPDATE EMP * SET ENAME = 'Thomas' * WHERE ENO = 21 END-EXEC CALL"SUB25"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code1 * EXEC SQL INSERT INTO EMP VALUES * (30,'Thomas','Languages & Operating System', * 12,'Computer',040523) END-EXEC CALL"SUB26"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL UPDATE EXPERIENCE * SET EXP_NAME = 'Thomas' * WHERE EXP_NAME = 'Tom' AND BTH_DATE = 040523 END-EXEC CALL"SUB27"USING SQLCODE MOVE SQLCODE TO SQL-COD MOVE SQLCODE TO code2 * EXEC SQL DELETE FROM EMP * WHERE ENO = 21 END-EXEC CALL"SUB28"USING SQLCODE MOVE SQLCODE TO SQL-COD * EXEC SQL SELECT COUNT(*) INTO :count1 * FROM EMP * WHERE DNO = 12 AND ENO = 21 * AND ENAME = 'Tom' END-EXEC CALL"SUB29"USING SQLCODE count1 MOVE SQLCODE TO SQL-COD * EXEC SQL ROLLBACK WORK; CALL"SUB30"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" The correct answer is :" DISPLAY" code1 is not equal to 0." DISPLAY" code2 is equal to 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" code1 is ", code1 DISPLAY" code2 is ", code2 DISPLAY" count1 is ", count1 if (code1 < 0 AND code2 = 0 AND count1 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0368','pass','MCO') END-EXEC CALL"SUB31"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0368','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB32"USING SQLCODE MOVE SQLCODE TO SQL-COD DISPLAY" cdr019.sco *** fail *** " END-IF DISPLAY"================================================"
DISPLAY" " * EXEC SQL COMMIT WORK; CALL"SUB33"USING SQLCODE MOVE SQLCODE TO SQL-COD ************************ END TEST0368 ************************
**** TESTER MAY CHOOSE TO INSERT CODE FOR errcnt > 0 STOPRUN.
* **** Procedures for PERFORM statements
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