#Example: "PqDescendants-treetraverse-i" . . . based on manual example
#(demonstrates how one may use the p-group generation machinery to
# traverse a descendants tree, by exploring the 3-groups of rank 2
# and 3-coclass 1 up to 3-class 5.)
#vars: G, procId;
#options:
G := ElementaryAbelianGroup( 9 );
procId := PqStart( G );
##
## Below, we use the option StepSize in order to construct descendants
## of coclass 1. This is equivalent to setting the StepSize to 1 in
## each descendant calculation.
##
## The elementary abelian group of order 9 has 3 descendants of
## 3-class 2 and 3-coclass 1, as the result of the next command
## shows.
##
PqDescendants( procId : StepSize := 1 );
##
## Now we will compute the descendants of coclass 1 for each of the
## groups above. Then we will compute the descendants of coclass 1
## of each descendant and so on. Note that the pq program keeps
## one file for each class at a time. For example, the descendants
## calculation for the second group of class 2 overwrites the
## descendant file obtained from the first group of class 2.
## Hence, we have to traverse the descendants tree in depth first
## order.
##
PqPGSetDescendantToPcp( procId, 2, 1 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 3, 1 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 4, 1 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## At this point we stop traversing the ``left most'' branch of the
## descendants tree and move upwards.
##
PqPGSetDescendantToPcp( procId, 4, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 3, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## The computations above indicate that the descendants subtree under
## the first descendant of the elementary abelian group of order 9
## will have only one path of infinite length.
##
PqPGSetDescendantToPcp( procId, 2, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## We get four descendants here, three of which will turn out to be
## incapable, i.e., they have no descendants and are terminal nodes
## in the descendants tree.
##
PqPGSetDescendantToPcp( procId, 2, 3 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## The third descendant of class three is incapable. Let us return
## to the second descendant of class 2.
##
PqPGSetDescendantToPcp( procId, 2, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 3, 1 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 3, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## We skip the third descendant for the moment ...
##
PqPGSetDescendantToPcp( procId, 3, 4 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## ... and look at it now.
##
PqPGSetDescendantToPcp( procId, 3, 3 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
##
## In this branch of the descendant tree we get 6 descendants of class
## three. Of those 5 will turn out to be incapable and one will have
## 7 descendants.
##
PqPGSetDescendantToPcp( procId, 4, 1 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 4, 2 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
PqPGSetDescendantToPcp( procId, 4, 3 );;
PqPGExtendAutomorphisms( procId );;
PqPGConstructDescendants( procId : StepSize := 1 );
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