# Black box algorithm to find standard generators of Co2
set F 0
set G 0
set V 0
set X 0
lbl SEMISTD
rand 1
ord 1 A
incr V
if V gt 1000 then timeout
if A notin 1 2 3 4 5 6 7 8 9 10 11 12 14 15 16 18 20 &
23 24 28 30 then fail
if F eq 0 then
if A in 16 18 28 then
div A 2 B
pwr B 1 2
set F 1
endif
endif
if G eq 0 then
if A in 15 30 then
div A 5 C
pwr C 1 3
set G 1
endif
endif
if F eq 0 then jmp SEMISTD
if G eq 0 then jmp SEMISTD
set Y 0
set Z 0
set U 0
lbl CONJUGATE
incr X
if X gt 1000 then timeout
incr Y
rand 4
cjr 3 4
mu 2 3 5
ord 5 D
if D notin 4 5 6 7 8 9 10 11 12 14 15 16 18 20 23 24 28 30 then fail
if D eq 7 then
set Z 1 # We are in the correct conjugacy class!
endif
if Z eq 0 then
if Y gt 35 then
set G 0
jmp SEMISTD
endif
# Certain product orders are much more likely to
# occur with 5B elements (and vice versa)
if D in 6 12 14 24 30 then incr U
if D in 9 11 15 23 then decr U
if U eq 3 then
# Probably a 5B element.
set G 0
jmp SEMISTD
endif
endif
if D noteq 28 then jmp CONJUGATE
# Once we've got y s.t. o(xy) = 28, we need to check
# o(xyy) = 9 if we don't yet know that y is in the right
# class.
if Z eq 0 then
mu 5 3 6 # abb
ord 6 E
if E notin 9 15 then fail
if E eq 15 then
set G 0
jmp SEMISTD
endif
endif
oup 2 2 3
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