/* SPDX-License-Identifier: GPL-2.0+ * * $Id: checksum.S,v 1.10 2001/07/06 13:11:32 gniibe Exp $ * * INET An implementation of the TCP/IP protocol suite for the LINUX * operating system. INET is implemented using the BSD Socket * interface as the means of communication with the user level. * * IP/TCP/UDP checksumming routines * * Authors: Jorge Cwik, <jorge@laser.satlink.net> * Arnt Gulbrandsen, <agulbra@nvg.unit.no> * Tom May, <ftom@netcom.com> * Pentium Pro/II routines: * Alexander Kjeldaas <astor@guardian.no> * Finn Arne Gangstad <finnag@guardian.no> * Lots of code moved from tcp.c and ip.c; see those files * for more names. * * Changes: Ingo Molnar, converted csum_partial_copy() to 2.1 exception * handling. * Andi Kleen, add zeroing on error * converted to pure assembler * * SuperH version: Copyright (C) 1999 Niibe Yutaka
*/
#include <asm/errno.h>
#include <linux/linkage.h>
/* * computes a partial checksum, e.g. for TCP/UDP fragments
*/
/* * unsigned int csum_partial(const unsigned char *buf, int len, * unsigned int sum);
*/
.text
ENTRY(csum_partial) /* * Experiments with Ethernet and SLIP connections show that buff * is aligned on either a 2-byte or 4-byte boundary. We get at * least a twofold speedup on 486 and Pentium if it is 4-byte aligned. * Fortunately, it is easy to convert 2-byte alignment to 4-byte * alignment for the unrolled loop.
*/
mov r5, r1
mov r4, r0
tst #2, r0 ! Check alignment.
bt 2f ! Jump if alignment is ok. !
add #-2, r5 ! Alignment uses up two bytes.
cmp/pz r5 !
bt/s 1f ! Jump if we had at least two bytes.
clrt
bra 6f
add #2, r5 ! r5 was < 2. Deal with it.
1:
mov r5, r1 ! Save new len for later use.
mov.w @r4+, r0
extu.w r0, r0
addc r0, r6
bf 2f
add #1, r6
2:
mov #-5, r0
shld r0, r5
tst r5, r5
bt/s 4f ! if it's =0, go to 4f
clrt
.align 2
3:
mov.l @r4+, r0
mov.l @r4+, r2
mov.l @r4+, r3
addc r0, r6
mov.l @r4+, r0
addc r2, r6
mov.l @r4+, r2
addc r3, r6
mov.l @r4+, r3
addc r0, r6
mov.l @r4+, r0
addc r2, r6
mov.l @r4+, r2
addc r3, r6
addc r0, r6
addc r2, r6
movt r0
dt r5
bf/s 3b
cmp/eq #1, r0 ! here, we know r5==0
addc r5, r6 ! add carry to r6
4:
mov r1, r0
and #0x1c, r0
tst r0, r0
bt/s 6f
mov r0, r5
shlr2 r5
mov #0, r2
5:
addc r2, r6
mov.l @r4+, r2
movt r0
dt r5
bf/s 5b
cmp/eq #1, r0
addc r2, r6
addc r5, r6 ! r5==0 here, so it means add carry-bit
6:
mov r1, r5
mov #3, r0
and r0, r5
tst r5, r5
bt 9f ! if it's =0 go to 9f
mov #2, r1
cmp/hs r1, r5
bf 7f
mov.w @r4+, r0
extu.w r0, r0
cmp/eq r1, r5
bt/s 8f
clrt
shll16 r0
addc r0, r6
7:
mov.b @r4+, r0
extu.b r0, r0
#ifndef __LITTLE_ENDIAN__
shll8 r0
#endif
8:
addc r0, r6
mov #0, r0
addc r0, r6
9:
rts
mov r6, r0
/* unsigned int csum_partial_copy_generic (const char *src, char *dst, int len)
*/
/* * Copy from ds while checksumming, otherwise like csum_partial with initial * sum being ~0U
*/
! ! r4: const char *SRC ! r5: char *DST ! r6: int LEN !
ENTRY(csum_partial_copy_generic)
mov #-1,r7
mov #3,r0 ! Check src and dest are equally aligned
mov r4,r1
and r0,r1
and r5,r0
cmp/eq r1,r0
bf 3f ! Different alignments, use slow version
tst #1,r0 ! Check dest word aligned
bf 3f ! If not, do it the slow way
mov #2,r0
tst r0,r5 ! Check dest alignment.
bt 2f ! Jump if alignment is ok.
add #-2,r6 ! Alignment uses up two bytes.
cmp/pz r6 ! Jump if we had at least two bytes.
bt/s 1f
clrt
add #2,r6 ! r6 was < 2. Deal with it.
bra 4f
mov r6,r2
3: ! Handle different src and dest alignments. ! This is not common, so simple byte by byte copy will do.
mov r6,r2
shlr r6
tst r6,r6
bt 4f
clrt
.align 2
5:
EXC( mov.b @r4+,r1 )
EXC( mov.b @r4+,r0 )
extu.b r1,r1
EXC( mov.b r1,@r5 )
EXC( mov.b r0,@(1,r5) )
extu.b r0,r0
add #2,r5
#ifdef __LITTLE_ENDIAN__
shll8 r0
#else
shll8 r1
#endif
or r1,r0
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