// Simple LinkedList type. (See the Q&A section to understand how this // differs from std::list). // // To use, start by declaring the class which will be contained in the linked // list, as extending LinkNode (this gives it next/previous pointers). // // class MyNodeType : public LinkNode<MyNodeType> { // ... // }; // // Next, to keep track of the list's head/tail, use a LinkedList instance: // // LinkedList<MyNodeType> list; // // To add elements to the list, use any of LinkedList::Append, // LinkNode::InsertBefore, or LinkNode::InsertAfter: // // LinkNode<MyNodeType>* n1 = ...; // LinkNode<MyNodeType>* n2 = ...; // LinkNode<MyNodeType>* n3 = ...; // // list.Append(n1); // list.Append(n3); // n2->InsertBefore(n3); // // Lastly, to iterate through the linked list forwards: // // for (LinkNode<MyNodeType>* node = list.head(); // node != list.end(); // node = node->next()) { // MyNodeType* value = node->value(); // ... // } // // Or to iterate the linked list backwards: // // for (LinkNode<MyNodeType>* node = list.tail(); // node != list.end(); // node = node->previous()) { // MyNodeType* value = node->value(); // ... // } // // Questions and Answers: // // Q. Should I use std::list or base::LinkedList? // // A. The main reason to use base::LinkedList over std::list is // performance. If you don't care about the performance differences // then use an STL container, as it makes for better code readability. // // Comparing the performance of base::LinkedList<T> to std::list<T*>: // // * Erasing an element of type T* from base::LinkedList<T> is // an O(1) operation. Whereas for std::list<T*> it is O(n). // That is because with std::list<T*> you must obtain an // iterator to the T* element before you can call erase(iterator). // // * Insertion operations with base::LinkedList<T> never require // heap allocations. // // Q. How does base::LinkedList implementation differ from std::list? // // A. Doubly-linked lists are made up of nodes that contain "next" and // "previous" pointers that reference other nodes in the list. // // With base::LinkedList<T>, the type being inserted already reserves // space for the "next" and "previous" pointers (base::LinkNode<T>*). // Whereas with std::list<T> the type can be anything, so the implementation // needs to glue on the "next" and "previous" pointers using // some internal node type.
namespace base {
namespace internal {
// Base class for LinkNode<T> type class BASE_EXPORT LinkNodeBase { public: void RemoveFromList();
// Calling these with |e| as a different LinkNode type as |this| is // unsafe. These are protected and only called from LinkNode<T> to // ensure safety. void InsertBeforeBase(LinkNodeBase* e); void InsertAfterBase(LinkNodeBase* e);
private: // `previous_` and `next_` are not a raw_ptr<...> for performance reasons: // on-stack pointer + a large number of non-PA pointees through WeakLinkNode + // based on analysis of sampling profiler data and tab_search:top100:2020.
RAW_PTR_EXCLUSION LinkNodeBase* previous_ = nullptr;
RAW_PTR_EXCLUSION LinkNodeBase* next_ = nullptr;
};
// Cast from the node-type to the value type. const T* value() const { returnstatic_cast<const T*>(this);
}
T* value() { returnstatic_cast<T*>(this);
}
};
template <typename T> class LinkedList { public: // The "root" node is self-referential, and forms the basis of a circular // list (root_.next() will point back to the start of the list, // and root_->previous() wraps around to the end of the list).
LinkedList() : root_(&root_, &root_) {}
LinkedList(const LinkedList&) = delete;
LinkedList& operator=(const LinkedList&) = delete;
// Appends |e| to the end of the linked list. void Append(LinkNode<T>* e) {
e->InsertBefore(&root_);
}
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