* Standard COBOL (file "CDR008.SCO") calling SQL * procedures in file "CDR008.MCO"
**************************************************************** * * COMMENT SECTION * * DATE 1989/04/07 STANDARD COBOL LANGUAGE * NIST SQL VALIDATION TEST SUITE V6.0 * DISCLAIMER: * This program was written by employees of NIST to test SQL * implementations for conformance to the SQL standards. * NIST assumes no responsibility for any party's use of * this program. * * CDR008.SCO * WRITTEN BY: SUN DAJUN * TRANSLATED AUTOMATICALLY FROM EMBEDDED COBOL BY CHRIS SCHANZLE * * THIS ROUTINE TESTS THE REFERENTIAL INTEGRITY CONSTRAINT FOR * SQL. * * REFERENCES * AMERICAN NATIONAL STANDARD database language - SQL * with Integrity Enhancement * * SECTION 6.7 <referential constraint definition> * <referential constraint definition>::= * FOREIGN KEY (<referencing columns>) * <references specification> * <references specification>::= * REFERENCES <referenced table and columns> * <referencing columns>::= * <reference column list> * <refereced table and columns>::= * <table name>((<reference column list> * <reference column list>::= * <column name>({,<column name>}...) * ****************************************************************
******************** BEGIN TEST0324 ******************* *This test inserts rows into FOREIGN KEY *TABLE -- WORKS3, there have been such a row *(P1,-,-,-,-) in PROJ,but no (P2,-,-,-,-) in PROJ
DISPLAY" TEST0324 " DISPLAY" PRIMARY KEY & FOREIGN KEY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" VALUES
- " ('P1','MASS','Design',10000,'Deale');" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E1','P1',40);" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" VALUES ('E2','P2',40);" DISPLAY" " DISPLAY" SELECT COUNT(*) INTO:count1" DISPLAY" FROM WORKS3" DISPLAY" WHERE PNUM = 'P2';" COMPUTE count1 = -1 * EXEC SQL DELETE FROM WORKS3; CALL"SUB12"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB13"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB14"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO PROJ3 * VALUES ('P1','MASS','Design',10000,'Deale') END-EXEC CALL"SUB15"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB16"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E1','P1',40) END-EXEC CALL"SUB17"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO WORKS3 * VALUES ('E2','P2',40) END-EXEC CALL"SUB18"USINGSQLCODE MOVESQLCODETO SQL-COD MOVESQLCODETO code1 * EXEC SQL SELECT COUNT(*) INTO:count1 * FROM WORKS3 * WHERE PNUM = 'P2' END-EXEC CALL"SUB19"USINGSQLCODE count1 MOVESQLCODETO SQL-COD DISPLAY" The correct answer is :" DISPLAY" SQLCODE is less than 0." DISPLAY" count1 is 0" DISPLAY" Your answer is :" DISPLAY" SQLCOD of second insert is ", code1 DISPLAY" count1 is ", count1 if (code1 < 0 AND count1 = 0) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0324','pass','MCO') END-EXEC CALL"SUB20"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0324','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB21"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
******************** BEGIN TEST0325 ********************* *This test deletes a row (E1,-,-,-) from PRIMARY KEY *TABLE -- STAFF3, but there are such rows (E1,*,*) in *FOREIGN KEY TABLE -- WORK3, this should be an ERROR.
DISPLAY" TEST0325 " DISPLAY" REFERENTIAL INTEGRITY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM PROJ3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" INSERT INTO PROJ3" DISPLAY" SELECT * FROM PROJ;" DISPLAY" " DISPLAY" INSERT INTO WORKS3" DISPLAY" SELECT * FROM WORKS;" DISPLAY" " DISPLAY" DELETE FROM STAFF3" DISPLAY" WHERE EMPNUM='E1';" DISPLAY" " DISPLAY"code1 = SQLCODE" DISPLAY" " DISPLAY" SELECT EMPNUM INTO :EMPNO1" DISPLAY" FROM STAFF3" DISPLAY" WHERE EMPNUM = 'E1';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB23"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM PROJ3; CALL"SUB24"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB25"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB26"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO PROJ3 * SELECT * FROM PROJ END-EXEC CALL"SUB27"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO WORKS3 * SELECT * FROM WORKS END-EXEC CALL"SUB28"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM STAFF3 * WHERE EMPNUM='E1' END-EXEC CALL"SUB29"USINGSQLCODE MOVESQLCODETO SQL-COD MOVESQLCODETO code1 MOVE"NV"TO EMPNO1 * EXEC SQL SELECT EMPNUM INTO :EMPNO1 * FROM STAFF3 * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB30"USINGSQLCODE EMPNO1 MOVESQLCODETO SQL-COD DISPLAY" The correct result is code1 not equal to 0" DISPLAY" Your answer is code1=", code1 if (code1 NOT = 0 AND EMPNO1 = "E1") then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0325','pass','MCO') END-EXEC CALL"SUB31"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0325','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB32"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
******************** BEGIN TEST0326 ********************* *This test set a row (E1,-,-,-) in PRIMARY KEY TABLE *-- STAFF3 to (E9,-,-,-), there is no such a row *(E1,*,*) in FOREIGN KEY TABLE -- WORK3.
DISPLAY" TEST0326 " DISPLAY" REFERENTIAL INTEGRITY " DISPLAY" SQL with Integrity Enhancement section
- " 6.5,6.6,6.7" DISPLAY" - - - - - - - - - - - - - - - - - - - - - " DISPLAY" " DISPLAY" DELETE FROM WORKS3;" DISPLAY" " DISPLAY" DELETE FROM STAFF3;" DISPLAY" " DISPLAY" INSERT INTO STAFF3" DISPLAY" SELECT * FROM STAFF;" DISPLAY" " DISPLAY" UPDATE STAFF3" DISPLAY" SET EMPNUM = 'E9'" DISPLAY" WHERE EMPNUM = 'E1';" DISPLAY" " DISPLAY"code1 = SQLCODE" DISPLAY" " DISPLAY" SELECT EMPNUM INTO :EMPNO1" DISPLAY" FROM STAFF3" DISPLAY" WHERE EMPNUM = 'E1';" * EXEC SQL DELETE FROM WORKS3; CALL"SUB34"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL DELETE FROM STAFF3; CALL"SUB35"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL INSERT INTO STAFF3 * SELECT * FROM STAFF END-EXEC CALL"SUB36"USINGSQLCODE MOVESQLCODETO SQL-COD * EXEC SQL UPDATE STAFF3 * SET EMPNUM = 'E9' * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB37"USINGSQLCODE MOVESQLCODETO SQL-COD MOVESQLCODETO code1 MOVE"NV"TO EMPNO1 * EXEC SQL SELECT EMPNUM INTO :EMPNO1 * FROM STAFF3 * WHERE EMPNUM = 'E1' END-EXEC CALL"SUB38"USINGSQLCODE EMPNO1 MOVESQLCODETO SQL-COD DISPLAY" The correct result is code1 equal to 0" DISPLAY" Your answer is code1=", code1 if (code1 = 0 AND (EMPNO1 = "NV")) then * EXEC SQL INSERT INTO TESTREPORT * VALUES('0326','pass','MCO') END-EXEC CALL"SUB39"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" *** pass *** " else * EXEC SQL INSERT INTO TESTREPORT * VALUES('0326','fail','MCO') END-EXEC ADD 1 TO errcnt CALL"SUB40"USINGSQLCODE MOVESQLCODETO SQL-COD DISPLAY" cdr008.sco *** fail *** " END-IF DISPLAY"================================================"
Die Informationen auf dieser Webseite wurden
nach bestem Wissen sorgfältig zusammengestellt. Es wird jedoch weder Vollständigkeit, noch Richtigkeit,
noch Qualität der bereit gestellten Informationen zugesichert.
Bemerkung:
Die farbliche Syntaxdarstellung und die Messung sind noch experimentell.