products/Sources/formale Sprachen/GAP/pkg/hap/www/SideLinks/About/aboutCoefficientSequence.html
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<td style ="vertical-align: top;" ><a
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<td
style ="text-align: center; vertical-align: top; color: rgb(0, 0, 102);" ><big ><span
style ="font-weight: bold;" >About HAP: Exact Cohomology Coefficient
Sequence<br >
</span ></big ></td >
<td style ="text-align: right; vertical-align: top;" ><a
href="aboutSuperperfect.html" ><small style ="color: rgb(0, 0, 102);" >next</small ></a><br >
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<big ><span style ="font-weight: bold;" ></span ></big ><br >
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<td
style ="vertical-align: top; background-color: rgb(255, 255, 255); text-align: left;" >A
short
exact
sequence
of
ZG-modules
<br >
<div style ="text-align: center;" >A >--> B -->> C<br >
<div style ="text-align: left;" >induces a long exact sequence of
cohomology groups<br >
<div style ="text-align: center;" >--> H<sup >n</sup >(G,A)
--> H<sup >n</sup >(G,B) --> H<sup >n</sup >(G,C) --> H<sup >n+1</sup >(G,A)
-->
.<br >
<br >
<div style ="text-align: left;" ><br >
<br >
The implementation of this sequence is joint work with <span
style ="font-weight: bold;" >Daher Al-Baydli</span >. </div >
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<td
style ="background-color: rgb(255, 255, 255); vertical-align: top;" >Consider
the
symmetric
group
G=S<sub >4</sub > and the sequence<br >
<div style ="text-align: center;" > Z/4Z
>-----> Z/8Z ---> Z/2Z<br >
<br >
</div >
of trivial ZG-modules. We can represent a ZG-module as a GOuterGroup.
The following commands use this representation to compute the induced
cohomology homomorphism<br >
<br >
<div style ="text-align: center;" >f: H<sup >3</sup >(S<sub >4</sub >,Z/4Z)
---->
H<sup >3</sup >(S<sub >4</sub >,Z/8Z)<br >
<br >
</div >
and determine that the image of this induced homomorphism has order 8
and that its kernel has order 2. <br >
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<td
style ="background-color: rgb(255, 255, 204); vertical-align: top;" >gap>
G:=SymmetricGroup(4);;<br >
gap> x:=(1,2,3,4,5,6,7,8);;<br >
gap> a:=Group(x^2);;<br >
gap> b:=Group(x);;<br >
gap> ahomb:=GroupHomomorphismByFunction(a,b,y->y);;<br >
gap> A:=TrivialGModuleAsGOuterGroup(G,a);;<br >
gap> B:=TrivialGModuleAsGOuterGroup(G,b);;<br >
gap> phi:=GOuterGroupHomomorphism();;<br >
gap> phi!.Source :=A;;<br >
gap> phi!.Target:=B;;<br >
gap> phi!.Mapping:=ahomb;;<br >
<br >
gap> Hphi:=CohomologyHomomorphism(phi,3);;<br >
<br >
gap> Size(ImageOfGOuterGroupHomomorphism(Hphi));<br >
8<br >
<br >
gap> Size(KernelOfGOuterGroupHomomorphism(Hphi));<br >
2<br >
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<td
style ="text-align: left; background-color: rgb(255, 255, 255); vertical-align: top;" >The
following
commands
then
compute
the
homomorphism<br >
<br >
<div style ="text-align: center;" >H<sup >3</sup >(S<sub >4</sub >,Z/8Z)
---->
H<sup >3</sup >(S<sub >4</sub >,Z/2Z)<br >
</div >
<br >
induced by <br >
<br >
<div style ="text-align: center;" >Z/4Z >----->
Z/8Z ---->> Z/2Z .<br >
<br >
<div style ="text-align: left;" >and determine that the kernel of
this homomorphsim has order 8. <br >
</div >
</div >
</td >
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<td
style ="background-color: rgb(255, 255, 204); vertical-align: top;" >gap>
bhomc:=NaturalHomomorphismByNormalSubgroup(b,a);<br >
gap> B:=TrivialGModuleAsGOuterGroup(G,b);<br >
gap> C:=TrivialGModuleAsGOuterGroup(G,Image(bhomc));<br >
gap> psi:=GOuterGroupHomomorphism();<br >
gap> psi!.Source :=B;<br >
gap> psi!.Target:=C;<br >
gap> psi!.Mapping:=bhomc;<br >
<br >
gap> Hpsi:=CohomologyHomomorphism(psi,3);<br >
<br >
gap> Size(KernelOfGOuterGroupHomomorphism(Hpsi));<br >
8<br >
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<td
style ="vertical-align: top; background-color: rgb(255, 255, 255);" >The
following commands then compute the connecting homomorphism<br >
<br >
<div style ="text-align: center;" >H<sup >2</sup >(S<sub >4</sub >,Z/2Z)
---->
H<sup >3</sup >(S<sub >4</sub >,Z/4Z)<br >
</div >
<br >
and determine that the image of this homomorphism has order 2.<br >
</td >
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<td
style ="vertical-align: top; background-color: rgb(255, 255, 204);" >gap>
delta:=ConnectingCohomologyHomomorphism(psi,2);;<br >
gap> Size(ImageOfGOuterGroupHomomorphism(delta));<br >
2<br >
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<td
style ="vertical-align: top; background-color: rgb(255, 255, 255);" >Note
that
the
various
orders are consistent with exactness of the sequence<br >
<br >
<div style ="text-align: center;" >H<sup >2</sup >(S<sub >4</sub >,Z/2Z)
---->
H<sup >3</sup >(S<sub >4</sub >,Z/4Z) ---->
H<sup >3</sup >(S<sub >4</sub >,Z/8Z) ---->
H<sup >3</sup >(S<sub >4</sub >,Z/2Z) </div >
<br >
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