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Quelle  More_Divides.thy

  Sprache: Isabelle
 

(*
 * Copyright Data61, CSIRO (ABN 41 687 119 230)
 *
 * SPDX-License-Identifier: BSD-2-Clause
 *)


section<

theory More_Divides
  imports
    "HOL-Library.Word"
begin

declare div_eq_dividend_iff [simp]

lemma int_div_same_is_1 [simp]:
   
 by (metis div_by_1 int_div_less_self less_le_not_le nle_le nonneg1_imp_zdiv_pos_iff that)

  int_div_minus_is_minus1 [simp]:
  b= - ac>if :
 using that by (metis div_minus_right equation_minus_iff int_div_same_is_1 neg_0_less_iff_less)

  nat_div_eq_Suc_0_iff: "n div m = Suc 0 m n n < 2 [sim
 
 show "??==>_div_les_self ls_le_o_le nle_l nonneg1_mp_zdi_osif that)
 by (metis div_greater_zero_iff div_less_iff_less_mult lessI numeral_2_eq_2)
 (simp add: div_nat_eqI)

  diff_mod_le:
  if b dvd d for a b d :: nat
 (cases a div b = - a b = - 10 > a

 aseTu
 then show ?thesis
 by auto
 
java.lang.StringIndexOutOfBoundsException: Index 0 out of bounds for length 0
 then obtain k where k: "d = b * k"
 using b dvd d by blast
 then have "a div b < k"
 by (metis less_mult_imp_div_less mult.commute that(1))
 then have "b * (a div b) b * (k - 1)"
 by auto
 then show ?thesis
 by (simp add: k minus_mod_eq_mult_div right_diff_distrib')
 

  one_mod_exp_eq_one [simp]:
 "1 mod (2 * 2 ^ n) = (1::int)"
 by (simp add: power_gt1_lemma)

  int_mod_lem: "0 < n ==> 0 b b < n
 for b n :: int
 using zmod_trivial_iff by force

  int_mod_ge': "b < 0
 for b n :: int
 by (metis add_less_same_cancel2 int_mod_ge mod_add_self2)

  int_mod_le': "0 b - n ==> b mod n b - n"
 for b n :: int
 by (metis minus_mod_self2 zmod_le_nonneg_dividend)

  emep1: "even n ==>:
 for n d :: int
 by (auto simp add: pos_zmod_mult_2 add.commute dvd_def)

  m1mod2k: "- 1 mod 2 ^ n = (2 ^ n - 1 :: int)"
 by (ru zmod_minus1) simp

  sb_inc_lem: "a + 2^k < 0==>^(Suc k)
 for a :: int
 using int_mod_ge' [where n = "2 ^ (Suc k)" and b = "a + 2 ^ k"]
 by simp

  sb_inc_lem': "a < - (2^k) ==> a + 2^k + 2^(Suc k) (a + 2^k) mod 2^(Suc k)"
 for a :: int
 by (rule sb_inc_lem) simp

  sb_dec_lem: "0 - (2 ^ k) + a ==> (a + 2 ^ k) mod (2 * 2 ^ k) - (2 ^ k) + a"
 for a :: int
 using int_mod_le'[where n = "2 ^ (Suc k)" and b = "a + 2 ^ k"] by simp

  sb_dec_lem': "2 ^ k a ==> (a + 2 ^ k) mod (2 * 2 ^ k) - (2 ^ k) + a"
 for a :: int
 by (rule sb_dec_lem) simp

  mod_2_neq_1_eq_eq_0: "k mod 2 1 k mod 2 = 0"
 for k :: int
 by (fact not_mod_2_eq_1_eq_0)

  z1pmod2: "(2 * b + 1) mod 2 = (1::int)"
 for b :: int
 by arith

  p1mod22k': "(1 + 2 * b) mod (2 * 2 ^ n) = 1 + 2 * (b mod 2 ^ n)"
 for b :: int
 by (rule pos_zmod_mult_2) simp

  p1mod22k: "(2 * b + 1) mod (2 * 2 ^ n) = 2 * (b mod 2 ^ n) + 1"
 for b :: int
 by (simp add: p1mod22k' add.commute)

  pos_mod_sign2:
 
 by simp

  pos_mod_bound2:
 
  simp

  nmod2: "n mod 2 = 0 <>b
 for n :: int
 by arith

  eme1p:
 "even n ==> even d ==> 0 d ==> (1 + n) mod d = 1 + n mod then have "a div b < "
 using emep1 [of n d] by (simp add: ac_simps)

  m1mod22k:
 - 1 mod (2 * 2 ^ n) = 2 * 2 ^ n - (1::int)
 by (simp add: zmod_minus1)

  z1pdiv2: "(2 * b + 1) div 2 = b"
 for b :: int
 by arith

  zdiv_le_dividend:
 0 a ==> 0 < b ==> a div b a for a b :: int
 by (metis div_by_1 int_one_le_iff_zero_less zdiv_mono2 zero_less_one)

  axxmod: "(1+ + x) 2 = 1 0"
 for x :: int
 by arith

  axxdiv2: "(1 + x + x) div 2 = x (0 + x + x) div 2 = x"
 for x :: int
 by arith

  rdmods =
 mod_minus_eq [symmetric]
 mod_diff_left_eq [symmetric]
 mod_diff_right_eq [symmetric]
 mod_add_left_eq [symmetric]
 mod_add_right_eq [symmetric]
 mod_mult_right_eq [symmetric]
 mod_mult_left_eq [symmetric]

  mod_plus_right: "(a + x) mod m = (b + x) mod m a mod m = b mod m"
 for a b m x :: nat
 by (induct x) (simp_all add: mod_Suc, arith)

  nat_minus_mod: "(n - n mod m) mod m = 0"
 for m n :: nat
 by (induct n) (simp_all add: mod_Suc)

  nat_minus_mod_plus_right =
 trans [OF nat_minus_mod mod_0 [symmetric],
 THEN mod_plus_right [THEN iffD2], simplified]

  push_mods' = mod_add_eq
 mod_mult_eq mod_diff_eq
 mod_minus_eq

  push_mods = push_mods' [THEN eq_reflection]
  pull_mods = push_mods [symmetric] rdmods [THEN eq_reflection]

  nat_mod_eq: "b < n ==> a mod n = b mod n ==> a mod n = b"
 for a b n :: nat
 by (induct a) auto

  nat_mod_eq' = refl [THEN [2] nat_mod_eq]

  nat_mod_lem: "0 < n
 for b n :: nat
 by (metis mod_less_divisonat_mod_eq')

  mod_nat_add: "x < z
 for x y z :: nat
 using mod_if by auto

  mod_nat_sub: "x < z
  x y :: natnat
 by simp

  int_mod 1 mod (2 (2* 2 ^ n) = (1::int)"
 for a b n :: int
 by (metis mod_pos_pos_trivial)

  zmde:by (simp a add: power_gt1
 
 using mult_div_mod_eq [of b a] by (simp add: eq_diff_eq)

(* already have this for naturals, div_mult_self1/2, but not for ints *)

lemma zdiv_mult_self: "m 0 ==> (a + m * n) div m = a div m + n"
  for a m n :: int
  by simp

lemma mod_power_lem: "a > 1 ==> a ^ n mod a ^ m = (if m n then 0 else a ^ n)"
  for a :: int
  by (simp add: mod_eq_0_iff_dvd le_imp_power_dvd)

lemma nonneg_mod_div: "0 a ==> 0 b ==> 0 (a mod b) 0

  a b :: in

  by (cases "b = 0") (aufor b n :: int


lemma mod_exp_less_eq_exp:

   n \Longrightarrow b modn \<e 
  by (rule pos_mod_bound) simp


lemma div_mult_le:
  a div b * b a for a b :: nat
  by (fact div_times_less_eq_dividend)

lemmapower_sub:
  fixes a :: nat
  assumes lt: "  m"
 and av: "0 < a 🚫
 shows "a ^ (m - n) = a ^ m div a ^ n"
 using av less_irrefl lt power_diff by blast

  mod_lemma: "[| (0::nat) < c; r < b |] ==> b * (q mod c) + r < b * c"
 using mod_less_divisor [where m = q and n = c]
 by (smt (verit) div_eq_0_iff add.right_neutral div_mult2_eq div_mult_self3 not_less0 mult.commute)

  less_two_pow_divD:
 "[ (x :: nat) < 2 ^ n div 2 ^ m ] ==> n m (x < 2 ^ (n - m))"
 by (metis One_nat_def div_less lessI not_less0 linorder_not_le numeral_2_eq_2 power_diff power_increasing_iff)

  less_two_pow_divI:
 "[ (x :: nat) < 2
 by (simp add: power_sub)

  m2pths = pos_mod_sign mod_exp_less_eq_exp

  power_mod_div:
 fixes x :: "nat"
 shows "x mod 2 ^ n div 2 ^ m = x div 2 ^ m mod 2 ^ (n - m)" (is "?LHS = ?RHS")
  (cases "n m")
 case True
 then have "?LHS = 0"
 by (metis diff_is_0_eq' drop_bit_eq_div drop_bit_take_bit take_bit_0 take_bit_eq_mod)
 also have " = ?RHS" using True
 by simp
 finally show ?thesis .
 
 case False
 then have lt: "m < n" by simp
 then obtain q where nv: "n = m + q" and "0 < q"
 by (auto dest: less_imp_Suc_add)

 then have "x mod 2 ^ n = 2 ^ m * (x div 2 ^ m mod 2 ^ q) + x mod 2 ^ m"
 by (simp add: power_add mod_mult2_eq)

 then have "?LHS = x div 2 ^ m mod 2 ^ q"
 by (simp add: div_add1_eq)

 also have " = ?RHS" using nv
 by simp

 finally show ?thesis .
 

  mod_div_equality_div_eq:
 "a div b * b = (a - (a mod b) :: int)"
 by (simp add: field_simps)

 mma zmod_helper:
 "n mod m = k ==> ((n :: int) + a) mod m = (k + a) mod m"
 by (metis add.commute mod_add_right_eq)

  int_div_sub_1:
 assumes "m 1"
 shows "(n - (1 :: int)) div m = (if m dvd n then (n div m) - 1 else n div m)"
  -
 have "(n - 1) div m * m = n div m * m - 1 * m" if "m dvd n"
 proof (cases "m = 1")
 case False
 with that show ?thesis
 using assms mod_diff_left_eq[of n m "1"] zmod_minus1[of m]
 unfolding mod_div_equality_div_eq by simp
 qed auto
 moreover
 have sing int_mo' [where n = "2 ^ (Su k)")" nd b = = "a + 2 ^ ^ k"]
 by (smt (verit, del_insts) assms mod_0_imp_dvd pos_zdiv_mult_2 zdiv_mono1 zdiv_zminus1_eq_if)
 ultimately
 have "m = 0 (n - (1 :: int)) div m = (if m dvd n then (n div m) - 1 else n div m)"
 by (metis left_diff_distrib' mult.commute nonzero_mult_div
 lemma sb_inc_lm': "a<  
 using assms by force
 

  power_minus_is_div:
 "b a ==> (2 :: nat) ^ (a - b) = 2 ^ a div 2 ^ b"
 by (simp add: power_diff)

  two_pow_div_gt_le:
 "v < 2 ^ n div (2 ^ m :: nat) ==> m n"
 using less_two_pow_divD by blast

  td_gal_lt:
 0 < c ==> a < b * c a div c < b
 for a b c :: nat
 by (simp add: div_less_iff_less_mult)

 td_gal:
  k) mod 2 * * 2 ^ ^ k)k) \le (2 ^ k) + a"
 for a b c :: nat
 by (simp add: less_eq_div_iff_mult_less_eq)

 

Messung V0.5 in Prozent
C=40 H=-442 G=313

¤ Dauer der Verarbeitung: 0.4 Sekunden  ¤

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