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\begin{document}
\title{Formal Proof of Dilworth's Theorem}
\author{Vivek Soorya Maadoori \and S. M. Meesum \and Shiv Pillai \and T. V. H. Prathamesh \and Aditya Swami}
\maketitle
\begin{abstract}
A \emph{chain} is defined as a totally ordered subset of a partially ordered set. A \emph{chain cover} refers to
a collection of chains of a partially ordered set whose union equals the entire set. A \emph{chain
decomposition} is a chain cover consisting of pairwise disjoint sets. An \emph{antichain} is a subset of
elements of a partially ordered set in which no two elements are comparable.
In 1950, Dilworth proved that in any finite partially ordered set, the cardinality of a largest antichain equals the cardinality of a smallest chain decomposition.\cite{dilworth1950}
In this paper, we formalise a proof of the theorem above, also known as \emph{Dilworth's theorem}, based
on a proof by Perles (1963) \cite{perles1963proof}. Our formalisation draws on the formalisation of Dilworth's theorem
for chain covers in Coq by Abhishek Kr. Singh \cite{singh2017fully}, and builds on the AFP entry containing formalisation of minimal and maximal elements in a set by Martin Desharnais \cite{Min_Max_Least_Greatest-AFP}. Our formalisation extends the prior work in Coq by including a formal proof of Dilworth's theorem for chain decomposition.
\end{abstract}
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\section*{Acknowledgement}
We would like thank Divakaran D. for valuable suggestions.
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