(* Title: HOL/Proofs/Extraction/Greatest_Common_Divisor.thy
Author: Stefan Berghofer, TU Muenchen
Author: Helmut Schwichtenberg, LMU Muenchen
*)
section \<open>Greatest common divisor\<close>
theory Greatest_Common_Divisor
imports QuotRem
begin
theorem greatest_common_divisor:
"\n::nat. Suc m < n \
\<exists>k n1 m1. k * n1 = n \<and> k * m1 = Suc m \<and>
(\<forall>l l1 l2. l * l1 = n \<longrightarrow> l * l2 = Suc m \<longrightarrow> l \<le> k)"
proof (induct m rule: nat_wf_ind)
case (1 m n)
from division obtain r q where h1: "n = Suc m * q + r" and h2: "r \ m"
by iprover
show ?case
proof (cases r)
case 0
with h1 have "Suc m * q = n" by simp
moreover have "Suc m * 1 = Suc m" by simp
moreover have "l * l1 = n \ l * l2 = Suc m \ l \ Suc m" for l l1 l2
by (cases l2) simp_all
ultimately show ?thesis by iprover
next
case (Suc nat)
with h2 have h: "nat < m" by simp
moreover from h have "Suc nat < Suc m" by simp
ultimately have "\k m1 r1. k * m1 = Suc m \ k * r1 = Suc nat \
(\<forall>l l1 l2. l * l1 = Suc m \<longrightarrow> l * l2 = Suc nat \<longrightarrow> l \<le> k)"
by (rule 1)
then obtain k m1 r1 where h1': "k * m1 = Suc m"
and h2': "k * r1 = Suc nat"
and h3': "\l l1 l2. l * l1 = Suc m \ l * l2 = Suc nat \ l \ k"
by iprover
have mn: "Suc m < n" by (rule 1)
from h1 h1' h2' Suc have "k * (m1 * q + r1) = n"
by (simp add: add_mult_distrib2 mult.assoc [symmetric])
moreover have "l \ k" if ll1n: "l * l1 = n" and ll2m: "l * l2 = Suc m" for l l1 l2
proof -
have "l * (l1 - l2 * q) = Suc nat"
by (simp add: diff_mult_distrib2 h1 Suc [symmetric] mn ll1n ll2m [symmetric])
with ll2m show "l \ k" by (rule h3')
qed
ultimately show ?thesis using h1' by iprover
qed
qed
extract greatest_common_divisor
text \<open>
The extracted program for computing the greatest common divisor is
@{thm [display] greatest_common_divisor_def}
\<close>
instantiation nat :: default
begin
definition "default = (0::nat)"
instance ..
end
instantiation prod :: (default, default) default
begin
definition "default = (default, default)"
instance ..
end
instantiation "fun" :: (type, default) default
begin
definition "default = (\x. default)"
instance ..
end
lemma "greatest_common_divisor 7 12 = (4, 3, 2)" by eval
end
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