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(* Title: HOL/ex/Arith_Examples.thy
Author: Tjark Weber
*)
section \<open>Arithmetic\<close>
theory Arith_Examples
imports Main
begin
text \<open>
The \<open>arith\<close> method is used frequently throughout the Isabelle
distribution. This file merely contains some additional tests and special
corner cases. Some rather technical remarks:
\<^ML>\<open>Lin_Arith.simple_tac\<close> is a very basic version of the tactic. It performs no
meta-to-object-logic conversion, and only some splitting of operators.
\<^ML>\<open>Lin_Arith.tac\<close> performs meta-to-object-logic conversion, full
splitting of operators, and NNF normalization of the goal. The \<open>arith\<close>
method combines them both, and tries other methods (e.g.~\<open>presburger\<close>)
as well. This is the one that you should use in your proofs!
An \<open>arith\<close>-based simproc is available as well (see \<^ML>\<open>Lin_Arith.simproc\<close>), which---for performance
reasons---however does even less splitting than \<^ML>\<open>Lin_Arith.simple_tac\<close>
at the moment (namely inequalities only). (On the other hand, it
does take apart conjunctions, which \<^ML>\<open>Lin_Arith.simple_tac\<close> currently
does not do.)
\<close>
subsection \<open>Splitting of Operators: \<^term>\<open>max\<close>, \<^term>\<open>min\<close>, \<^term>\<open>abs\<close>,
\<^term>\<open>minus\<close>, \<^term>\<open>nat\<close>, \<^term>\<open>modulo\<close>,
\<^term>\<open>divide\<close>\<close>
lemma "(i::nat) <= max i j"
by linarith
lemma "(i::int) <= max i j"
by linarith
lemma "min i j <= (i::nat)"
by linarith
lemma "min i j <= (i::int)"
by linarith
lemma "min (i::nat) j <= max i j"
by linarith
lemma "min (i::int) j <= max i j"
by linarith
lemma "min (i::nat) j + max i j = i + j"
by linarith
lemma "min (i::int) j + max i j = i + j"
by linarith
lemma "(i::nat) < j ==> min i j < max i j"
by linarith
lemma "(i::int) < j ==> min i j < max i j"
by linarith
lemma "(0::int) <= \i\"
by linarith
lemma "(i::int) <= \i\"
by linarith
lemma "\\i::int\\ = \i\"
by linarith
text \<open>Also testing subgoals with bound variables.\<close>
lemma "!!x. (x::nat) <= y ==> x - y = 0"
by linarith
lemma "!!x. (x::nat) - y = 0 ==> x <= y"
by linarith
lemma "!!x. ((x::nat) <= y) = (x - y = 0)"
by linarith
lemma "[| (x::nat) < y; d < 1 |] ==> x - y = d"
by linarith
lemma "[| (x::nat) < y; d < 1 |] ==> x - y - x = d - x"
by linarith
lemma "(x::int) < y ==> x - y < 0"
by linarith
lemma "nat (i + j) <= nat i + nat j"
by linarith
lemma "i < j ==> nat (i - j) = 0"
by linarith
lemma "(i::nat) mod 0 = i"
using split_mod [of _ _ 0, arith_split]
\<comment> \<open>rule \<^text>\<open>split_mod\<close> is only declared by default for numerals\<close>
by linarith
lemma "(i::nat) mod 1 = 0"
(* rule split_mod is only declared by default for numerals *)
using split_mod [of _ _ 1, arith_split]
\<comment> \<open>rule \<^text>\<open>split_mod\<close> is only declared by default for numerals\<close>
by linarith
lemma "(i::nat) mod 42 <= 41"
by linarith
lemma "(i::int) mod 0 = i"
using split_zmod [of _ _ 0, arith_split]
\<comment> \<open>rule \<^text>\<open>split_zmod\<close> is only declared by default for numerals\<close>
by linarith
lemma "(i::int) mod 1 = 0"
using split_zmod [of _ _ "1", arith_split]
\<comment> \<open>rule \<^text>\<open>split_zmod\<close> is only declared by default for numerals\<close>
by linarith
lemma "(i::int) mod 42 <= 41"
by linarith
lemma "-(i::int) * 1 = 0 ==> i = 0"
by linarith
lemma "[| (0::int) < \i\; \i\ * 1 < \i\ * j |] ==> 1 < \i\ * j"
by linarith
subsection \<open>Meta-Logic\<close>
lemma "x < Suc y == x <= y"
by linarith
lemma "((x::nat) == z ==> x ~= y) ==> x ~= y | z ~= y"
by linarith
subsection \<open>Various Other Examples\<close>
lemma "(x < Suc y) = (x <= y)"
by linarith
lemma "[| (x::nat) < y; y < z |] ==> x < z"
by linarith
lemma "(x::nat) < y & y < z ==> x < z"
by linarith
text \<open>This example involves no arithmetic at all, but is solved by
preprocessing (i.e. NNF normalization) alone.\<close>
lemma "(P::bool) = Q ==> Q = P"
by linarith
lemma "[| P = (x = 0); (~P) = (y = 0) |] ==> min (x::nat) y = 0"
by linarith
lemma "[| P = (x = 0); (~P) = (y = 0) |] ==> max (x::nat) y = x + y"
by linarith
lemma "[| (x::nat) ~= y; a + 2 = b; a < y; y < b; a < x; x < b |] ==> False"
by linarith
lemma "[| (x::nat) > y; y > z; z > x |] ==> False"
by linarith
lemma "(x::nat) - 5 > y ==> y < x"
by linarith
lemma "(x::nat) ~= 0 ==> 0 < x"
by linarith
lemma "[| (x::nat) ~= y; x <= y |] ==> x < y"
by linarith
lemma "[| (x::nat) < y; P (x - y) |] ==> P 0"
by linarith
lemma "(x - y) - (x::nat) = (x - x) - y"
by linarith
lemma "[| (a::nat) < b; c < d |] ==> (a - b) = (c - d)"
by linarith
lemma "((a::nat) - (b - (c - (d - e)))) = (a - (b - (c - (d - e))))"
by linarith
lemma "(n < m & m < n') | (n < m & m = n') | (n < n' & n' < m) |
(n = n' & n' < m) | (n = m & m < n') |
(n' < m & m < n) | (n' < m & m = n) |
(n' < n & n < m) | (n' = n & n < m) | (n' = m & m < n) |
(m < n & n < n') | (m < n & n' = n) | (m < n' & n' < n) |
(m = n & n < n') | (m = n' & n' < n) |
(n' = m & m = (n::nat))"
(* FIXME: this should work in principle, but is extremely slow because *)
(* preprocessing negates the goal and tries to compute its negation *)
(* normal form, which creates lots of separate cases for this *)
(* disjunction of conjunctions *)
(* by (tactic {* Lin_Arith.tac 1 *}) *)
oops
lemma "2 * (x::nat) ~= 1"
(* FIXME: this is beyond the scope of the decision procedure at the moment, *)
(* because its negation is satisfiable in the rationals? *)
(* by (tactic {* Lin_Arith.simple_tac 1 *}) *)
oops
text \<open>Constants.\<close>
lemma "(0::nat) < 1"
by linarith
lemma "(0::int) < 1"
by linarith
lemma "(47::nat) + 11 < 8 * 15"
by linarith
lemma "(47::int) + 11 < 8 * 15"
by linarith
text \<open>Splitting of inequalities of different type.\<close>
lemma "[| (a::nat) ~= b; (i::int) ~= j; a < 2; b < 2 |] ==>
a + b <= nat (max \<bar>i\<bar> \<bar>j\<bar>)"
by linarith
text \<open>Again, but different order.\<close>
lemma "[| (i::int) ~= j; (a::nat) ~= b; a < 2; b < 2 |] ==>
a + b <= nat (max \<bar>i\<bar> \<bar>j\<bar>)"
by linarith
end
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