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products/sources/formale Sprachen/Isabelle/HOL/Data_Structures/ (Beweissystem Isabelle Version 2025-1^©) Datei vom 16.11.2025 mit Größe 26 kB

Quelle Array_Braun.thy Sprache: Isabelle

(* Author: Tobias Nipkow, with contributions by Thomas Sewell *)

section "Arrays via Braun Trees"

theory Array_Braun
imports
  "HOL-Library.Time_Functions"
  Array_Specs
  Braun_Tree
begin

subsection "Array"

fun lookup1 :: "'a tree \ nat \ 'a" where
  "lookup1 (Node l x r) n = (if n=1 then x else lookup1 (if even n then l else r) (n div 2))"

fun update1 :: "nat \ 'a \ 'a tree \ 'a tree" where
  "update1 n x Leaf = Node Leaf x Leaf" |
  "update1 n x (Node l a r) =
  (if n=1 then Node l x r else
   if even n then Node (update1 (n div 2) x l) a r
            else Node l a (update1 (n div 2) x r))"

fun adds :: "'a list \ nat \ 'a tree \ 'a tree" where
  "adds [] n t = t" |
  "adds (x#xs) n t = adds xs (n+1) (update1 (n+1) x t)"

fun list :: "'a tree \ 'a list" where
  "list Leaf = []" |
  "list (Node l x r) = x # splice (list l) (list r)"

subsubsection "Functional Correctness"

lemma size_list: "size(list t) = size t"
  by(induction t)(auto)

lemma minus1_div2: "(n - Suc 0) div 2 = (if odd n then n div 2 else n div 2 - 1)"
  by auto arith

lemma nth_splice: "\ n < size xs + size ys; size ys \ size xs; size xs \ size ys + 1 \
  \<Longrightarrow> splice xs ys ! n = (if even n then xs else ys) ! (n div 2)"
proof(induction xs ys arbitrary: n rule: splice.induct)
qed (auto simp: nth_Cons' minus1_div2)

lemma div2_in_bounds:
  "\ braun (Node l x r); n \ {1..size(Node l x r)}; n > 1 \ \
   (odd n \<longrightarrow> n div 2 \<in> {1..size r}) \<and> (even n \<longrightarrow> n div 2 \<in> {1..size l})"
  by auto arith

declare upt_Suc[simp del]

paragraph \<open>\<^const>\<open>lookup1\<close>\<close>

lemma nth_list_lookup1: "\braun t; i < size t\ \ list t ! i = lookup1 t (i+1)"
proof(induction t arbitrary: i)
  case Leaf thus ?case by simp
next
  case Node
  thus ?case using div2_in_bounds[OF Node.prems(1), of "i+1"]
    by (auto simp: nth_splice minus1_div2 size_list)
qed

lemma list_eq_map_lookup1: "braun t \ list t = map (lookup1 t) [1..
  by(auto simp add: list_eq_iff_nth_eq size_list nth_list_lookup1)

paragraph \<open>\<^const>\<open>update1\<close>\<close>

lemma size_update1: "\ braun t; n \ {1.. size t} \ \ size(update1 n x t) = size t"
proof(induction t arbitrary: n)
  case Leaf thus ?case by simp
next
  case Node thus ?case using div2_in_bounds[OF Node.prems] by simp
qed

lemma braun_update1: "\braun t; n \ {1.. size t} \ \ braun(update1 n x t)"
proof(induction t arbitrary: n)
  case Leaf thus ?case by simp
next
  case Node thus ?case
    using div2_in_bounds[OF Node.prems] by (simp add: size_update1)
qed

lemma lookup1_update1: "\ braun t; n \ {1.. size t} \ \
  lookup1 (update1 n x t) m = (if n=m then x else lookup1 t m)"
proof(induction t arbitrary: m n)
  case Leaf
  then show ?case by simp
next
  have aux: "\ odd n; odd m \ \ n div 2 = (m::nat) div 2 \ m=n" for m n
    using odd_two_times_div_two_succ by fastforce
  case Node
  thus ?case using div2_in_bounds[OF Node.prems] by (auto simp: aux)
qed

lemma list_update1: "\ braun t; n \ {1.. size t} \ \ list(update1 n x t) = (list t)[n-1 := x]"
  by(auto simp add: list_eq_map_lookup1 list_eq_iff_nth_eq lookup1_update1 size_update1 braun_update1)

text \<open>A second proof of @{thm list_update1}:\<close>

lemma diff1_eq_iff: "n > 0 \ n - Suc 0 = m \ n = m+1"
  by arith

lemma list_update_splice:
  "\ n < size xs + size ys; size ys \ size xs; size xs \ size ys + 1 \ \
  (splice xs ys) [n := x] =
  (if even n then splice (xs[n div 2 := x]) ys else splice xs (ys[n div 2 := x]))"
  by(induction xs ys arbitrary: n rule: splice.induct) (auto split: nat.split)

lemma list_update2: "\ braun t; n \ {1.. size t} \ \ list(update1 n x t) = (list t)[n-1 := x]"
proof(induction t arbitrary: n)
  case Leaf thus ?case by simp
next
  case (Node l a r) thus ?case using div2_in_bounds[OF Node.prems]
    by(auto simp: list_update_splice diff1_eq_iff size_list split: nat.split)
qed

paragraph \<open>\<^const>\<open>adds\<close>\<close>

lemma splice_last: shows
  "size ys \ size xs \ splice (xs @ [x]) ys = splice xs ys @ [x]"
  and "size ys+1 \ size xs \ splice xs (ys @ [y]) = splice xs ys @ [y]"
  by(induction xs ys arbitrary: x y rule: splice.induct) (auto)

lemma list_add_hi: "braun t \ list(update1 (Suc(size t)) x t) = list t @ [x]"
  by(induction t)(auto simp: splice_last size_list)

lemma size_add_hi: "braun t \ m = size t \ size(update1 (Suc m) x t) = size t + 1"
  by(induction t arbitrary: m)(auto)

lemma braun_add_hi: "braun t \ braun(update1 (Suc(size t)) x t)"
  by(induction t)(auto simp: size_add_hi)

lemma size_braun_adds:
  "\ braun t; size t = n \ \ size(adds xs n t) = size t + length xs \ braun (adds xs n t)"
  by(induction xs arbitrary: t n)(auto simp: braun_add_hi size_add_hi)

lemma list_adds: "\ braun t; size t = n \ \ list(adds xs n t) = list t @ xs"
  by(induction xs arbitrary: t n)(auto simp: size_braun_adds list_add_hi size_add_hi braun_add_hi)

subsubsection "Array Implementation"

interpretation A: Array
  where lookup = "\(t,l) n. lookup1 t (n+1)"
    and update = "\n x (t,l). (update1 (n+1) x t, l)"
    and len = "\(t,l). l"
    and array = "\xs. (adds xs 0 Leaf, length xs)"
    and invar = "\(t,l). braun t \ l = size t"
    and list = "\(t,l). list t"
proof (standard, goal_cases)
  case 1 thus ?case by (simp add: nth_list_lookup1 split: prod.splits)
next
  case 2 thus ?case by (simp add: list_update1 split: prod.splits)
next
  case 3 thus ?case by (simp add: size_list split: prod.splits)
next
  case 4 thus ?case by (simp add: list_adds)
next
  case 5 thus ?case by (simp add: braun_update1 size_update1 split: prod.splits)
next
  case 6 thus ?case by (simp add: size_braun_adds split: prod.splits)
qed

subsection "Flexible Array"

fun add_lo where
  "add_lo x Leaf = Node Leaf x Leaf" |
  "add_lo x (Node l a r) = Node (add_lo a r) x l"

fun merge where
  "merge Leaf r = r" |
  "merge (Node l a r) rr = Node rr a (merge l r)"

fun del_lo where
  "del_lo Leaf = Leaf" |
  "del_lo (Node l a r) = merge l r"

fun del_hi :: "nat \ 'a tree \ 'a tree" where
  "del_hi n Leaf = Leaf" |
  "del_hi n (Node l x r) =
  (if n = 1 then Leaf
   else if even n
       then Node (del_hi (n div 2) l) x r
       else Node l x (del_hi (n div 2) r))"

subsubsection "Functional Correctness"

paragraph \<open>\<^const>\<open>add_lo\<close>\<close>

lemma list_add_lo: "braun t \ list (add_lo a t) = a # list t"
  by(induction t arbitrary: a) auto

lemma braun_add_lo: "braun t \ braun(add_lo x t)"
  by(induction t arbitrary: x) (auto simp add: list_add_lo simp flip: size_list)

paragraph \<open>\<^const>\<open>del_lo\<close>\<close>

lemma list_merge: "braun (Node l x r) \ list(merge l r) = splice (list l) (list r)"
  by (induction l r rule: merge.induct) auto

lemma braun_merge: "braun (Node l x r) \ braun(merge l r)"
  by (induction l r rule: merge.induct)(auto simp add: list_merge simp flip: size_list)

lemma list_del_lo: "braun t \ list(del_lo t) = tl (list t)"
  by (cases t) (simp_all add: list_merge)

lemma braun_del_lo: "braun t \ braun(del_lo t)"
  by (cases t) (simp_all add: braun_merge)

paragraph \<open>\<^const>\<open>del_hi\<close>\<close>

lemma list_Nil_iff: "list t = [] \ t = Leaf"
  by(cases t) simp_all

lemma butlast_splice: "butlast (splice xs ys) =
  (if size xs > size ys then splice (butlast xs) ys else splice xs (butlast ys))"
  by(induction xs ys rule: splice.induct) (auto)

lemma list_del_hi: "braun t \ size t = st \ list(del_hi st t) = butlast(list t)"
  by (induction t arbitrary: st) (auto simp: list_Nil_iff size_list butlast_splice)

lemma braun_del_hi: "braun t \ size t = st \ braun(del_hi st t)"
  by (induction t arbitrary: st) (auto simp: list_del_hi simp flip: size_list)

subsubsection "Flexible Array Implementation"

interpretation AF: Array_Flex
  where lookup = "\(t,l) n. lookup1 t (n+1)"
    and update = "\n x (t,l). (update1 (n+1) x t, l)"
    and len = "\(t,l). l"
    and array = "\xs. (adds xs 0 Leaf, length xs)"
    and invar = "\(t,l). braun t \ l = size t"
    and list = "\(t,l). list t"
    and add_lo = "\x (t,l). (add_lo x t, l+1)"
    and del_lo = "\(t,l). (del_lo t, l-1)"
    and add_hi = "\x (t,l). (update1 (Suc l) x t, l+1)"
    and del_hi = "\(t,l). (del_hi l t, l-1)"
proof (standard, goal_cases)
  case 1 thus ?case by (simp add: list_add_lo split: prod.splits)
next
  case 2 thus ?case by (simp add: list_del_lo split: prod.splits)
next
  case 3 thus ?case by (simp add: list_add_hi braun_add_hi split: prod.splits)
next
  case 4 thus ?case by (simp add: list_del_hi split: prod.splits)
next
  case 5 thus ?case by (simp add: braun_add_lo list_add_lo flip: size_list split: prod.splits)
next
  case 6 thus ?case by (simp add: braun_del_lo list_del_lo flip: size_list split: prod.splits)
next
  case 7 thus ?case by (simp add: size_add_hi braun_add_hi split: prod.splits)
next
  case 8 thus ?case by (simp add: braun_del_hi list_del_hi flip: size_list split: prod.splits)
qed

subsection "Faster"

subsubsection \<open>Size\<close>

fun diff :: "'a tree \ nat \ nat" where
  "diff Leaf _ = 0" |
  "diff (Node l x r) n = (if n=0 then 1 else if even n then diff r (n div 2 - 1) else diff l (n div 2))"

fun size_fast :: "'a tree \ nat" where
  "size_fast Leaf = 0" |
  "size_fast (Node l x r) = (let n = size_fast r in 1 + 2*n + diff l n)"

declare Let_def[simp]

lemma diff: "braun t \ size t : {n, n + 1} \ diff t n = size t - n"
  by (induction t arbitrary: n) auto

lemma size_fast: "braun t \ size_fast t = size t"
  by (induction t) (auto simp add: diff)

subsubsection \<open>Initialization with 1 element\<close>

fun braun_of_naive :: "'a \ nat \ 'a tree" where
  "braun_of_naive x n = (if n=0 then Leaf
  else let m = (n-1) div 2
       in if odd n then Node (braun_of_naive x m) x (braun_of_naive x m)
       else Node (braun_of_naive x (m + 1)) x (braun_of_naive x m))"

fun braun2_of :: "'a \ nat \ 'a tree * 'a tree" where
  "braun2_of x n = (if n = 0 then (Leaf, Node Leaf x Leaf)
  else let (s,t) = braun2_of x ((n-1) div 2)
       in if odd n then (Node s x s, Node t x s) else (Node t x s, Node t x t))"

definition braun_of :: "'a \ nat \ 'a tree" where
  "braun_of x n = fst (braun2_of x n)"

declare braun2_of.simps [simp del]

lemma braun2_of_size_braun: "braun2_of x n = (s,t) \ size s = n \ size t = n+1 \ braun s \ braun t"
proof(induction x n arbitrary: s t rule: braun2_of.induct)
  case (1 x n)
  then show ?case
    by (auto simp: braun2_of.simps[of x n] split: prod.splits if_splits) presburger+
qed

lemma braun2_of_replicate:
  "braun2_of x n = (s,t) \ list s = replicate n x \ list t = replicate (n+1) x"
proof(induction x n arbitrary: s t rule: braun2_of.induct)
  case (1 x n)
  have "x # replicate m x = replicate (m+1) x" for m by simp
  with 1 show ?case
    apply (auto simp: braun2_of.simps[of x n] replicate.simps(2)[of 0 x]
        simp del: replicate.simps(2) split: prod.splits if_splits)
    by presburger+
qed

corollary braun_braun_of: "braun(braun_of x n)"
  unfolding braun_of_def by (metis eq_fst_iff braun2_of_size_braun)

corollary list_braun_of: "list(braun_of x n) = replicate n x"
  unfolding braun_of_def by (metis eq_fst_iff braun2_of_replicate)

subsubsection "Proof Infrastructure"

text \<open>Originally due to Thomas Sewell.\<close>

paragraph \<open>\<open>take_nths\<close>\<close>

fun take_nths :: "nat \ nat \ 'a list \ 'a list" where
  "take_nths i k [] = []" |
  "take_nths i k (x # xs) = (if i = 0 then x # take_nths (2^k - 1) k xs
  else take_nths (i - 1) k xs)"

text \<open>This is the more concise definition but seems to complicate the proofs:\<close>

lemma take_nths_eq_nths: "take_nths i k xs = nths xs (\n. {n*2^k + i})"
proof(induction xs arbitrary: i)
  case Nil
  then show ?case by simp
next
  case (Cons x xs)
  show ?case
  proof cases
    assume [simp]: "i = 0"
    have "\x n. Suc x = n * 2 ^ k \ \xa. x = Suc xa * 2 ^ k - Suc 0"
      by (metis diff_Suc_Suc diff_zero mult_eq_0_iff not0_implies_Suc)
    then have "(\n. {(n+1) * 2 ^ k - 1}) = {m. \n. Suc m = n * 2 ^ k}"
      by (auto simp del: mult_Suc)
    thus ?thesis by (simp add: Cons.IH ac_simps nths_Cons)
  next
    assume [arith]: "i \ 0"
    have "\x n. Suc x = n * 2 ^ k + i \ \xa. x = xa * 2 ^ k + i - Suc 0"
      by (metis diff_Suc_Suc diff_zero)
    then have "(\n. {n * 2 ^ k + i - 1}) = {m. \n. Suc m = n * 2 ^ k + i}"
      by auto
    thus ?thesis by (simp add: Cons.IH nths_Cons)
  qed
qed

lemma take_nths_drop:
  "take_nths i k (drop j xs) = take_nths (i + j) k xs"
  by (induct xs arbitrary: i j; simp add: drop_Cons split: nat.split)

lemma take_nths_00:
  "take_nths 0 0 xs = xs"
  by (induct xs; simp)

lemma splice_take_nths:
  "splice (take_nths 0 (Suc 0) xs) (take_nths (Suc 0) (Suc 0) xs) = xs"
  by (induct xs; simp)

lemma take_nths_take_nths:
  "take_nths i m (take_nths j n xs) = take_nths ((i * 2^n) + j) (m + n) xs"
  by (induct xs arbitrary: i j; simp add: algebra_simps power_add)

lemma take_nths_empty:
  "(take_nths i k xs = []) = (length xs \ i)"
  by (induction xs arbitrary: i k) auto

lemma hd_take_nths:
  "i < length xs \ hd(take_nths i k xs) = xs ! i"
  by (induction xs arbitrary: i k) auto

lemma take_nths_01_splice:
  "\ length xs = length ys \ length xs = length ys + 1 \ \
   take_nths 0 (Suc 0) (splice xs ys) = xs \<and>
   take_nths (Suc 0) (Suc 0) (splice xs ys) = ys"
  by (induct xs arbitrary: ys; case_tac ys; simp)

lemma length_take_nths_00:
  "length (take_nths 0 (Suc 0) xs) = length (take_nths (Suc 0) (Suc 0) xs) \
   length (take_nths 0 (Suc 0) xs) = length (take_nths (Suc 0) (Suc 0) xs) + 1"
  by (induct xs) auto

paragraph \<open>\<open>braun_list\<close>\<close>

fun braun_list :: "'a tree \ 'a list \ bool" where
  "braun_list Leaf xs = (xs = [])" |
  "braun_list (Node l x r) xs = (xs \ [] \ x = hd xs \
    braun_list l (take_nths 1 1 xs) \<and>
    braun_list r (take_nths 2 1 xs))"

lemma braun_list_eq:
  "braun_list t xs = (braun t \ xs = list t)"
proof (induct t arbitrary: xs)
  case Leaf
  show ?case by simp
next
  case Node
  show ?case
    using length_take_nths_00[of xs] splice_take_nths[of xs]
    by (auto simp: neq_Nil_conv Node.hyps size_list[symmetric] take_nths_01_splice)
qed

subsubsection \<open>Converting a list of elements into a Braun tree\<close>

fun nodes :: "'a tree list \ 'a list \ 'a tree list \ 'a tree list" where
  "nodes (l#ls) (x#xs) (r#rs) = Node l x r # nodes ls xs rs" |
  "nodes (l#ls) (x#xs) [] = Node l x Leaf # nodes ls xs []" |
  "nodes [] (x#xs) (r#rs) = Node Leaf x r # nodes [] xs rs" |
  "nodes [] (x#xs) [] = Node Leaf x Leaf # nodes [] xs []" |
  "nodes ls [] rs = []"

fun brauns :: "nat \ 'a list \ 'a tree list" where
  "brauns k xs = (if xs = [] then [] else
   let ys = take (2^k) xs;
       zs = drop (2^k) xs;
       ts = brauns (k+1) zs
   in nodes ts ys (drop (2^k) ts))"

declare brauns.simps[simp del]

definition brauns1 :: "'a list \ 'a tree" where
  "brauns1 xs = (if xs = [] then Leaf else brauns 0 xs ! 0)"

paragraph "Functional correctness"

text \<open>The proof is originally due to Thomas Sewell.\<close>

lemma length_nodes:
  "length (nodes ls xs rs) = length xs"
  by (induct ls xs rs rule: nodes.induct; simp)

lemma nth_nodes:
  "i < length xs \ nodes ls xs rs ! i =
  Node (if i < length ls then ls ! i else Leaf) (xs ! i)
    (if i < length rs then rs ! i else Leaf)"
  by (induct ls xs rs arbitrary: i rule: nodes.induct;
      simp add: nth_Cons split: nat.split)

theorem length_brauns:
  "length (brauns k xs) = min (length xs) (2 ^ k)"
proof (induct xs arbitrary: k rule: measure_induct_rule[where f=length])
  case (less xs) thus ?case by (simp add: brauns.simps[of k xs] length_nodes)
qed

theorem brauns_correct:
  "i < min (length xs) (2 ^ k) \ braun_list (brauns k xs ! i) (take_nths i k xs)"
proof (induct xs arbitrary: i k rule: measure_induct_rule[where f=length])
  case (less xs)
  have "xs \ []" using less.prems by auto
  let ?zs = "drop (2^k) xs"
  let ?ts = "brauns (Suc k) ?zs"
  from less.hyps[of ?zs _ "Suc k"]
  have IH: "\ j = i + 2 ^ k; i < min (length ?zs) (2 ^ (k+1)) \ \
    braun_list (?ts ! i) (take_nths j (Suc k) xs)" for i j
    using \<open>xs \<noteq> []\<close> by (simp add: take_nths_drop)
  show ?case
    using less.prems
    by (auto simp: brauns.simps[of k xs] nth_nodes take_nths_take_nths
        IH take_nths_empty hd_take_nths length_brauns)
qed

corollary brauns1_correct:
  "braun (brauns1 xs) \ list (brauns1 xs) = xs"
  using brauns_correct[of 0 xs 0]
  by (simp add: brauns1_def braun_list_eq take_nths_00)

paragraph "Running Time Analysis"

time_fun_0 "(^)"

time_fun nodes

lemma T_nodes: "T_nodes ls xs rs = length xs + 1"
by(induction ls xs rs rule: T_nodes.induct) auto

time_fun brauns

lemma T_brauns_simple: "T_brauns k xs = (if xs = [] then 0 else
   3 * (min (2^k) (length xs) + 1) + (min (2^k) (length xs - 2^k) + 1) + T_brauns (k+1) (drop (2^k) xs)) + 1"
by(simp add: T_nodes T_take T_drop length_brauns min_def)

theorem T_brauns_ub:
  "T_brauns k xs \ 9 * (length xs + 1)"
proof (induction xs arbitrary: k rule: measure_induct_rule[where f = length])
  case (less xs)
  show ?case
  proof cases
    assume "xs = []"
    thus ?thesis by(simp)
  next
    assume "xs \ []"
    let ?n = "length xs" let ?zs = "drop (2^k) xs"
    have *: "?n - 2^k + 1 \ ?n"
      using \<open>xs \<noteq> []\<close> less_eq_Suc_le by fastforce
    have "T_brauns k xs =
      3 * (min (2^k) ?n + 1) + (min (2^k) (?n - 2^k) + 1) + T_brauns (k+1) ?zs + 1"
      unfolding T_brauns_simple[of k xs] using \<open>xs \<noteq> []\<close> by(simp del: T_brauns.simps)
    also have "\ \ 4 * min (2^k) ?n + T_brauns (k+1) ?zs + 5"
      by(simp add: min_def)
    also have "\ \ 4 * min (2^k) ?n + 9 * (length ?zs + 1) + 5"
      using less[of ?zs "k+1"] \<open>xs \<noteq> []\<close>
      by (simp del: T_brauns.simps)
    also have "\ = 4 * min (2^k) ?n + 9 * (?n - 2^k + 1) + 5"
      by(simp)
    also have "\ = 4 * min (2^k) ?n + 4 * (?n - 2^k) + 5 * (?n - 2^k + 1) + 9"
      by(simp)
    also have "\ = 4 * ?n + 5 * (?n - 2^k + 1) + 9"
      by(simp)
    also have "\ \ 4 * ?n + 5 * ?n + 9"
      using * by(simp)
    also have "\ = 9 * (?n + 1)"
      by (simp add: Suc_leI)
    finally show ?thesis .
  qed
qed

subsubsection \<open>Converting a Braun Tree into a List of Elements\<close>

text \<open>The code and the proof are originally due to Thomas Sewell (except running time).\<close>

function list_fast_rec :: "'a tree list \ 'a list" where
  "list_fast_rec ts = (let us = filter (\t. t \ Leaf) ts in
  if us = [] then [] else
  map value us @ list_fast_rec (map left us @ map right us))"
  by (pat_completeness, auto)

lemma list_fast_rec_term1: "ts \ [] \ Leaf \ set ts \
  sum_list (map (size o left) ts) + sum_list (map (size o right) ts) < sum_list (map size ts)"
  apply (clarsimp simp: sum_list_addf[symmetric] sum_list_map_filter')
  apply (rule sum_list_strict_mono; clarsimp?)
  apply (case_tac x; simp)
  done

lemma list_fast_rec_term: "us \ [] \ us = filter (\t. t \ \\) ts \
  sum_list (map (size o left) us) + sum_list (map (size o right) us) < sum_list (map size ts)"
  apply (rule order_less_le_trans, rule list_fast_rec_term1, simp_all)
  apply (rule sum_list_filter_le_nat)
  done

termination
  by (relation "measure (sum_list o map size)"; simp add: list_fast_rec_term)

declare list_fast_rec.simps[simp del]

definition list_fast :: "'a tree \ 'a list" where
  "list_fast t = list_fast_rec [t]"

(* TODO: map and filter are a problem!
- The automatically generated T_map is slightly more complicated than needed.
- We cannot use the manually defined T_map directly because the automatic translation
  assumes that T_map has a more complicated type and generates a "wrong" call.
Therefore we hide map/filter at the moment.
*)

definition "filter_not_Leaf = filter (\t. t \ Leaf)"

definition "map_left = map left"
definition "map_right = map right"
definition "map_value = map value"

definition "T_filter_not_Leaf ts = length ts + 1"
definition "T_map_left ts = length ts + 1"
definition "T_map_right ts = length ts + 1"
definition "T_map_value ts = length ts + 1"
(*
time_fun "tree.value"
time_fun "left"
time_fun "right"
*)

lemmas defs = filter_not_Leaf_def map_left_def map_right_def map_value_def
  T_filter_not_Leaf_def T_map_value_def T_map_left_def T_map_right_def

(* A variant w/o explicit map/filter; T_list_fast_rec is generated from it *)
lemma list_fast_rec_simp:
"list_fast_rec ts = (let us = filter_not_Leaf ts in
  if us = [] then [] else
  map_value us @ list_fast_rec (map_left us @ map_right us))"
unfolding defs list_fast_rec.simps[of ts] by(rule refl)

time_function list_fast_rec equations list_fast_rec_simp
termination
  by (relation "measure (sum_list o map size)"; simp add: list_fast_rec_term defs)

declare T_list_fast_rec.simps[simp del]

paragraph "Functional Correctness"

lemma list_fast_rec_all_Leaf:
  "\t \ set ts. t = Leaf \ list_fast_rec ts = []"
  by (simp add: filter_empty_conv list_fast_rec.simps)

lemma take_nths_eq_single:
  "length xs - i < 2^n \ take_nths i n xs = take 1 (drop i xs)"
  by (induction xs arbitrary: i n; simp add: drop_Cons')

lemma braun_list_Nil:
  "braun_list t [] = (t = Leaf)"
  by (cases t; simp)

lemma braun_list_not_Nil: "xs \ [] \
  braun_list t xs =
     (\<exists>l x r. t = Node l x r \<and> x = hd xs \<and>
        braun_list l (take_nths 1 1 xs) \<and>
        braun_list r (take_nths 2 1 xs))"
  by(cases t; simp)

theorem list_fast_rec_correct:
  "\ length ts = 2 ^ k; \i < 2 ^ k. braun_list (ts ! i) (take_nths i k xs) \
    \<Longrightarrow> list_fast_rec ts = xs"
proof (induct xs arbitrary: k ts rule: measure_induct_rule[where f=length])
  case (less xs)
  show ?case
  proof (cases "length xs < 2 ^ k")
    case True
    from less.prems True have filter:
      "\n. ts = map (\x. Node Leaf x Leaf) xs @ replicate n Leaf"
      apply (rule_tac x="length ts - length xs" in exI)
      apply (clarsimp simp: list_eq_iff_nth_eq)
      apply(auto simp: nth_append braun_list_not_Nil take_nths_eq_single braun_list_Nil hd_drop_conv_nth)
      done
    thus ?thesis
      by (clarsimp simp: list_fast_rec.simps[of ts] o_def list_fast_rec_all_Leaf)
  next
    case False
    with less.prems(2) have *:
      "\i < 2 ^ k. ts ! i \ Leaf
         \<and> value (ts ! i) = xs ! i
         \<and> braun_list (left (ts ! i)) (take_nths (i + 2 ^ k) (Suc k) xs)
         \<and> (\<forall>ys. ys = take_nths (i + 2 * 2 ^ k) (Suc k) xs
                 \<longrightarrow> braun_list (right (ts ! i)) ys)"
      by (auto simp: take_nths_empty hd_take_nths braun_list_not_Nil take_nths_take_nths
          algebra_simps)
    have 1: "map value ts = take (2 ^ k) xs"
      using less.prems(1) False by (simp add: list_eq_iff_nth_eq *)
    have 2: "list_fast_rec (map left ts @ map right ts) = drop (2 ^ k) xs"
      using less.prems(1) False
      by (auto intro!: Nat.diff_less less.hyps[where k= "Suc k"]
          simp: nth_append * take_nths_drop algebra_simps)
    from less.prems(1) False show ?thesis
      by (auto simp: list_fast_rec.simps[of ts] 1 2 * all_set_conv_all_nth)
  qed
qed

corollary list_fast_correct:
  "braun t \ list_fast t = list t"
  by (simp add: list_fast_def take_nths_00 braun_list_eq list_fast_rec_correct[where k=0])

paragraph "Running Time Analysis"

lemma sum_tree_list_children: "\t \ set ts. t \ Leaf \
  (\<Sum>t\<leftarrow>ts. k * size t) = (\<Sum>t \<leftarrow> map left ts @ map right ts. k * size t) + k * length ts"
  by(induction ts)(auto simp add: neq_Leaf_iff algebra_simps)

theorem T_list_fast_rec_ub:
  "T_list_fast_rec ts \ sum_list (map (\t. 14*size t + 1) ts) + 2"
proof (induction ts rule: measure_induct_rule[where f="sum_list o map size"])
  case (less ts)
  let ?us = "filter (\t. t \ Leaf) ts"
  show ?case
  proof cases
    assume "?us = []"
    thus ?thesis using T_list_fast_rec.simps[of ts]
      by(simp add: defs sum_list_Suc)
  next
    assume "?us \ []"
    let ?children = "map left ?us @ map right ?us"
    have 1: "1 \ length ?us"
      using \<open>?us \<noteq> []\<close> linorder_not_less by auto
    have "T_list_fast_rec ts = T_list_fast_rec ?children + 5 * length ?us + length ts + 7"
      using \<open>?us \<noteq> []\<close> T_list_fast_rec.simps[of ts] by(simp add: defs T_append)
    also have "\ \ (\t\?children. 14 * size t + 1) + 5 * length ?us + length ts + 9"
      using less[of "?children"] list_fast_rec_term[of "?us"] \<open>?us \<noteq> []\<close>
      by (simp)
    also have "\ = (\t\?children. 14 * size t) + 7 * length ?us + length ts + 9"
      by(simp add: sum_list_Suc o_def)
    also have "\ \ (\t\?children. 14 * size t) + 14 * length ?us + length ts + 2"
      using 1 by(simp add: sum_list_Suc o_def)
    also have "\ = (\t\?us. 14 * size t) + length ts + 2"
      by(simp add: sum_tree_list_children)
    also have "\ \ (\t\ts. 14 * size t) + length ts + 2"
      by(simp add: sum_list_filter_le_nat)
    also have "\ = (\t\ts. 14 * size t + 1) + 2"
      by(simp add: sum_list_Suc)
    finally show ?case .
  qed
qed

end

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